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PtichkaEL [24]
2 years ago
12

Which of the following tables represents a function?

Mathematics
2 answers:
nirvana33 [79]2 years ago
7 0

Answer:

B

Step-by-step explanation:

Every time the y-value increases by one, the function multiplies the x-value by -1

RUDIKE [14]2 years ago
3 0

Answer:

Option D

Step-by-step explanation:

cause in function one single domain can have many range but many range can't have single domain.

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A right triangle has a hypotenuse length of 13 units. One leg has a length of 12 units. Which equation can be used to determine
irinina [24]

Answer:

The length of the other leg is 12

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3 years ago
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The volume of a cube is 64 cubic feet. What is the edge length of the cube​
Kobotan [32]

area 4 ft

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3 years ago
Quadrilateral TRAM is rotated -90 degrees about the origin. Draw the image of this rotation.
SpyIntel [72]

Answer:

Please find attached the image of the quadrilateral TRAM after a rotation of -90 degrees, created with MS Excel

Step-by-step explanation:

The given coordinates of the vertices of the quadrilateral TRAM are;

T(-5, 1), R(-7, 7), A(-1, 7), M(-5, 4)

By a rotation of -90 degrees = Rotation of 90 degrees clockwise, we get;

The coordinates of the preimage before rotation = (x, y)

The coordinates of the image after rotation = (y, -x)

Therefore, we get for the the quadrilateral T'R'A'M', by rotating TRAM -90 degrees as follows;

T(-5, 1) → T'(1, 5)

R(-7, 7) → R'(7, 7)

A(-1, 7) → A'(7, 1)

M(-5, 4) → M'(4, 5)

The image of TRAM after -90 degrees rotation is created by plotting the derived points of the quadrilateral T'R'A'M' on MS Excel and joining the corresponding points as presented in the attached diagram.

7 0
3 years ago
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8 0
3 years ago
If a point P(x,y) is the equidistant from the points A(2,3) and B(6,1), find the equation of locus of moving point P.​
jekas [21]

Answer:

y=2x-6

Step-by-step explanation:

A locus can be defined as a curve or figure formed by all the points satisfying a particular equation of the relation between coordinates.

The condition stated in the question is such that a generic (x,y) point of the curve is equidistant from the points A(2,3) and B(6,1).

The distance d1 from (x,y) to (2,3) is:

d_1=\sqrt{(x-2)^2+(y-3)^2}

The distance d2 from (x,y) to (6,1) is:

d_2=\sqrt{(x-6)^2+(y-1)^2}

Since d1=d2:

\sqrt{(x-2)^2+(y-3)^2}=\sqrt{(x-6)^2+(y-1)^2}

Squaring both sides:

(x-2)^2+(y-3)^2=(x-6)^2+(y-1)^2

Operating:

x^2-4x+4+y^2-6y+9=x^2-12x+36+y^2-2y+1

Simplifying all the squares:

-4x+4x+4-6y+9=-12x+36-2y+1

Moving the variables to the left side and the numbers to the right side:

-4x+12x-6y+2y=36+1-4-9

Simplifying:

8x-4y=24

Dividing by 4:

2x-y=6

Or, equivalently:

\boxed{y=2x-6}

7 0
3 years ago
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