The answer is
D. Phenotype
Trust me a took a test with the same question and got it right!
P ( fail U infection ) = P ( fail ) + P ( infection ) - P ( fail AND infection )
==>
0.03 + 0.16 - 0.01 = -.18
==>
P ( success AND infection-free )
==>
1 - 0.18 = 0.82
==>
Therefore, 82 percent of these operations succeed and are free from infection.
Rats account for a decent amount of biomass globally. They are intermediate predators, eating a lot but also being eaten. If they went extinct, they would stop eating many insects and seeds / fruits -- the former would gain significantly in population, and the latter would lose some of their pollination. Both factors would harm the viability of at least some species of plants, by adding to plant eaters (insects) and reducing plant reproduction. Rats' predators would also suffer if they went extinct. The primary predators are birds of prey, such as hawks and owls. However, other animals such as skunks, foxes, weasels, coyotes, and even wolves eat rats. For predators in marginal environments, the loss of such a food source could drive them out of a habitat area.
Answer:
The balance form of the equation is given below.
Pb(NO3)2+2KI ——-> 2KNO3 + PbI2
Explanation:
In this equation lead nitrate and potassium iodide are reactants while potassium nitrate and lead iodide are the products. In the unbalanced form of equation, two molecule of iodine are formed in the product whereas there is only one molecule of iodine is present in the reactant. So for balancing this, 2 value is put in front of potassium iodide but by putting 2, potassium is also double in the reactant so 2 is also placed in front of potassium nitrate in the product and the equation is balanced.