


Let the marked prize of the TV be x .

We have SP = MP - Discount



<em>Hence </em><em>,</em><em> </em><em>T</em><em>he </em><em>marked</em><em> </em><em>prize</em><em> </em><em>of </em><em>the </em><em>TV </em><em>is </em><em>₹</em><em>2</em><em>0</em><em>,</em><em>2</em><em>5</em><em>0</em><em> </em><em>.</em>
<em>Hope </em><em>it </em><em>helps </em><em>~</em><em> </em>
The new pool is 18.84 feet larger in circumference than the old one.
<u>Explanation:</u>
Given:
Circumference of the pool = 47.1 feet
Diameter of the new pool, d = 21 feet
radius, r = 21/2 feet
Circumference of the new pool = ?
We know:
Circumference = 2πr
where,
r is the radius
On substituting the value:
C = 
C = 65.94 feet
The difference in circumference of the two pools = 65.94 - 47.1 feet
= 18.84 feet
Therefore, the new pool is 18.84 feet larger in circumference than the old one.
Answer:
Step-by-step explanation:
Hey B is the correct answer as the x is negative and y is positive
Hope this helps!!!
Use the tangent-chord theorem:
The included chord-tangent angle is half the size of the intercepted arc.
The intercepted arc is "c".
The included chord-tangent-angle is the supplement of 110=70 degrees.
Therefore from the tangent-chord theorem, 70 degrees = half the size of arc "c"
=>
arc "c" = 2*intercepted angle = 2*70 degrees = 140 degrees.