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Firdavs [7]
3 years ago
10

Predict the products and balance the equation classify the reaction

Chemistry
1 answer:
Rzqust [24]3 years ago
8 0

Answer:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

Explanation:

Hello there!

In this case, when coming across combustion reactions whereby hydrocarbons as fuels are burnt in the presence of oxygen, the main products are said to be carbon dioxide and water in agreement to the breaking and rearrangement of bonds due to the collisions among molecules. Thus, for the reaction between propane and oxygen we have the following balanced reaction:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

Best regards!

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How many moles of ammonia, NH,, are contained in<br><br> 6.21 x 1024 molecules of ammonia?
ankoles [38]

Answer:

10.32 moles of ammonia NH₃

Explanation:

From the question given above, the following data were obtained:

Number of molecules = 6.21×10²⁴ molecules

Number of mole of NH₃ =?

The number of mole of NH₃ can be obtained as follow:

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole

Therefore,

6.21×10²⁴ molecules = 6.21×10²⁴ / 6.02×10²³

6.21×10²⁴ molecules = 10.32 moles

Thus, 6.21×10²⁴ molecules contains 10.32 moles of ammonia NH₃

6 0
2 years ago
A closed vessel having a volume of 1 liter holds 2.5 × 1022 molecules of carbon dioxide gas. Determine the mass of CO2 present,
11111nata11111 [884]

Answer:

mass = 1.8x10⁻³ kg; number of moles = 4.1x10⁻⁵ kmol; specific volume = 0.55 m³/kg; molar specific volume = 24.4 m³/kmol

Explanation:

By the Avogadro's number, 1 mol of the matter has 6.02x10²³ molecules, thus, the number of moles (n) is the number of molecules presented divided by Avogadro's number:

n = 2.5x10²²/6.02x10²³

n = 0.041 mol

n = 4.1x10⁻⁵ kmol

The molar mass of CO₂ is 44 g/mol (12 g/mol of C + 2*16g/mol of O), and the mass is the number of moles multiplied by the molar mass:

m = 0.041 mol * 44 g/mol

m = 1.804 g

m = 1.8x10⁻³ kg

The specific volume (v) is the volume (1L = 0.001 m³) divided by the mass, and it represents how much volume is presented in each part of the mass:

v = 0.001/1.8x10⁻³

v = 0.55 m³/kg

The molar specific volume (nv) is the volume divided by the number of moles, and it represents how much volume is presented in each part of the mol:

nv = 0.001/4.1x10⁻⁵

nv = 24.4 m³/kmol

5 0
3 years ago
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