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-Dominant- [34]
3 years ago
6

How many moles of HNO3 are present in 450 g of HNO3?

Chemistry
1 answer:
iVinArrow [24]3 years ago
6 0
Since there are 63.01284 grams to one mole of HNO3, then 12.5 moles would be in 450 grams of it.
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Which of the following is true of a gas?
mote1985 [20]

Answer:

d

Explanation:

6 0
3 years ago
Write the balanced oxidation-reduction reaction equation for the oxidation of benzoin by ammonium nitrate. 2
Margarita [4]
<span>Benzoin<span> is an organic compound with the formula PhCH(OH)C(O)Ph. It is a hydroxy ketone attached to two phenyl groups.</span><span>

To answer your question, </span><span>the balanced oxidation-reduction reaction equation for the oxidation of benzoin by ammonium nitrate is:

</span>2Ph-C(OH)-C(O)-Ph+NH4NO3 --> 2Ph-C(O)-C(O)-Ph + N2 + 3H2O.</span>

<span>
</span><span>I hope this helps and if you have any further questions, please don’t hesitate to ask again.</span>

7 0
3 years ago
In a cold pack, which type of reaction draws heat from the surroundings?
Bingel [31]
That would be an endothermic reaction! :)
6 0
3 years ago
2. A 2.5 mol SAMPLE OF OXYGEN GAS (O2) INCREASES TO 3.2 mol
lana [24]

696.32 mmHg is the final pressure of the gas.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas.

Given data:

P_1 = 720 mmHg              

P_2 = ?

n_1 = 2.5 mol                

n_2 = 3.2 mol

V_1 = 34 L            

V_2 = 45 L

Formula

Combined gas law

\frac{P_1 V_1}{n_1}  = \frac{P_2 V_2}{n_2}

P_2 = 696.32 mmHg

Hence, 696.32 mmHg is the final pressure of the gas.

Learn more about an ideal gas equation here:

brainly.com/question/19251972

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6 0
2 years ago
Calculate the number of moles of carbon dioxide formed when 40.0 moles of oxygen is consumed in the burning of propane. Note the
joja [24]
The first step is to balance the equation:


<span>C3H8 + 5O2 ---> 3CO2 + 4H2O


Check the balance


element          left side        right side

C                    3                  3  
H                    8                  4*2 = 8
O                    5*2=10        3*2 + 4 = 10


Then you have the molar ratios:


3 mol C3H8 : 5 mol O2 : 3 mol CO2 : 4 mol H2O


Now you have 40 moles of O2 so you make the proportion:

40.0 mol O2 * [3 mol CO2 / 5 mol O2] = 24.0 mol CO2.


Answer: option D. 24.0 mol CO2
</span>
7 0
3 years ago
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