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4 years ago

Why is basalt a sign that the moon once had magma at its surface14 points

1 answer:

7 0

The basalt is a sign that the Moon once had magma at its surface because the basalt is a type of rock that forms directly from the cooling off of the magma. The basalt is part of the igneous type of rocks, which are the type of rocks that form from the cooling of the magma, be it on the surface or inside the ground, so having basalt on the Moon is a sure sign that our natural satellite once had magma on it.

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Is the statement correct or incorrect? Explain. A) It is correct. The ashes weigh less than the original wood and this proves th

Vladimir79 [104]

The correct answer is D

According to the law of conservation of mass, mass can not be destroyed or lost, it can just be rearranged in space, turned into energy etc.

Therefore, in our of example the wood was burned and turned into ashes. Even though the ashes weight less than the original wood, some of the solid mass of the wood was converted to gas and energy, so the overall mass remained the same.

7 0

3 years ago

Explain how the quantum mechanical model of the atom describes the electron structure of an atom

taurus [48]

Electrons are NOT in circular orbits around nucleus. -Theatomic orbital describes the probable location of the electrion Quantum Mechanical Model of the Atom Page 3 There are different kinds of atomic orbitals that differ in the amount of energy and shapes (where the electron probably is).

7 0

4 years ago

Describe what would happen if the particles in cold water lost enough heat to freeze

Mazyrski [523]

The atoms will form intermolecular bonds and solidify

4 0

3 years ago

A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

Answer: The mass of glucose in final solution is 0.420 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

4 years ago

Need help with these two problems

maw [93]

1.The atomic numbers

7 0

4 years ago