<h3><u>Answer</u> :</h3>
![\bigstar\:\boxed{\bf{\purple{x^{\frac{m}{n}}}=\orange{(\sqrt[n]{x})^m}}}](https://tex.z-dn.net/?f=%5Cbigstar%5C%3A%5Cboxed%7B%5Cbf%7B%5Cpurple%7Bx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%7D%3D%5Corange%7B%28%5Csqrt%5Bn%5D%7Bx%7D%29%5Em%7D%7D%7D)
Let's solve !
![:\implies\sf\:(\sqrt[2]{25})^3](https://tex.z-dn.net/?f=%3A%5Cimplies%5Csf%5C%3A%28%5Csqrt%5B2%5D%7B25%7D%29%5E3)
<u>Hence, Oprion-D is correct</u> !
Answer:
7) (f+g)(x) = 4^x +5x -5
8) (f-g)(x) = 4^x +x +5
Step-by-step explanation:
7) add the two expressions.
(f+g)(x) = f(x) +g(x) = (4^x +3x) +(2x -5)
(f+g)(x) = 4^x +5x -5
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8) subtract g(x) from f(x).
(f-g)(x) = f(x) -g(x) = (4^x +3x) -(2x -5) = 4^x +3x -2x +5
(f-g)(x) = 4^x +x +5
Answer:
the nominator could be any number here
M - 12 = -3
You would be able to find what m is by finding a number that can subtract 12 and get -3.
Hope this helps and have a nice day!!!
Answer:
1) S(t) = C(t) × D(t)
2) S(t) = (400 + 30t)(25 + t)
Step-by-step explanation:
The function C(t) = 400 + 30t ........... (1), models the number of classrooms, C. in the town of Sirap, t years from now.
The function D(t) = 25 + t ......... (2) models the number of students per classroom, D, t years from now.
Then if S(t) represents the number of students in Sirap's school system t years from now, then, we can write the relation
1) S(t) = C(t) × D(t) (Answer)
2) Hence, the formula of S(t) in terms if t is given by
S(t) = (400 + 30t)(25 + t) (Answer)
