The interval where the function is nonlinear and decreasing is 0 < x < 4
<h3>How to determine the interval where the function is nonlinear and decreasing?</h3>
The straight lines on the graph are the intervals where the graph is linear
This means that the straight lines on the graph will not be considered
Considering the curve, the graph decrease from x = 0 to x = 4
This can be rewritten as:
0 < x < 4
Hence, the interval where the function is nonlinear and decreasing is 0 < x < 4
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Answer: 8 > u > 6. I hope it helps!
Answer:
B
Step-by-step explanation:
multiply both sides by 2 to eliminate the fraction
- x > 12
multiply both sides by - 1
Remembering to reverse the inequality symbol as a consequence
x < - 12 ← reverse symbol
⇒ { x | x ∈ R, x < - 12 } → B
Step-by-step explanation:
the 2 angles marked with orange and green are equal becos the question said that the indicated angles are congruent meaning same deg. so 180 - that given angle = the 2 marked angles (based on the rule known as angles on a str line are supplementary)
since the 2 marked angles are same, you can say that d and k are parallel due to the rule of alternate angles
Topic: angle properties
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