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3 years ago

Angle Relationship Equations ... pose help I don’t do this but my friend has to so help

Mathematics

2 answers:

Naddika [18.5K]3 years ago

4 0

26 + ( 3x + 1 ) = 180

27 + 3x = 180

3x = 180 - 27

3x = 153

x = 153/3

x = 51

___________________

( 4x + 1 ) + ( 3x + 4 ) = 180

7x + 5 = 180

7x = 180 - 5

7x = 175

x = 175/5

x = 25

eduard3 years ago

4 0

Answer:

3) $x=51$

4) $x=25$

Step-by-step explanation:

$3) ~ 3x+1+26=180\\ \\ ~ (linear ~pair)$

$3x+27=180\\~ ~ -27 ~ ~-27$

$subtract ~ -27 ~ from ~ both ~ sides$

$\frac{3x}{3} =\frac{153}{3}$

$x=51$

$4)~ 4x+1+4+3x=180$

$7x=180-5$

$x=\frac{175}{7}$

$x=25$

hope it helps...

have a great day!!

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Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this: