Answer:
1) Increase
2) Decreases
3) increases
4) Increase
Explanation:
These questions can only be answered by considering the principle which states that, "When a constraint such as a change in concentration, pressure or volume is imposed on a reaction system in equilibrium. The system will readjust itself in order to annul the constraint."
Now, if more reactants are added, the equilibrium position will shift towards the right, If more products are added, the equilibrium position will shift to the left.
Similarly, the removal of H2S causes the O2 concentration to increase since the equilibrium position now shifts to the left.
Also, addition of O2 causes H2S to be removed as the equilibrium moves to the right.
That illustration represents the mitochondria
Answer:
The empirical formula of the hydrocarbon is CH.
Explanation:
The following data were obtained from the question:
Mass of hydrocarbon = 2.9 mg
Mass of CO2 = 9.803 mg
Mass of H2O = 2.006 mg
Next, we shall determine the mass of carbon (C) and hydrogen (H) in the compound since hydrocarbon contains carbon and hydrogen only.
This is illustrated below:
Molar mass of CO2 = 12 + (16x2) = 12 + 32 = 44 g/mol
Mass of CO2 = 9.803 mg
Mass of C in the compound =?
Mass of C in the compound =
12/44 x 9.803
= 2.674 mg
Molar mass of H2O = (2x1) + 16 = 2 + 16 = 18 g/mol
Mass of H2O = 2.006 mg
Mass of H in the compound =
2/18 x 2.006
= 0.223 mg
Finally, we shall determine the empirical formula of the hydrocarbon as follow:
Carbon (C) = 2.674 mg
Hydrogen (H) = 0.223 mg
Divide by their molar mass
C = 2.674 /12 = 0.223
H = 0.223 / 1 = 0.223
Divide both side by the the smallest
C = 0.223/0.223 = 1
H = 0.223/0.223 = 1
Therefore, the empirical formula of the hydrocarbon is CH.
I believe the correct answer is C it would make the value of the left side equal to 4 and the value to the right side also equal to 4
