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wariber [46]
3 years ago
14

What effect does the pH of water have on radish seed germination?

Chemistry
1 answer:
natka813 [3]3 years ago
8 0
It has a high percentage of germination in pH’s 13-14 this shows that radish seeds can germinate very well in almost all pH levels
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How many grams of KBr are required to make 350. mL of a 0.115 M KBr solution?
Vsevolod [243]
0.115 M means that 0.115 moles of KBr are contained in a volume of 1000 ml, therefore a volume of 350 ml will have (0.115 × 0.35) = 04025 moles
From the formula of molarity moles = molarity × volume in liters
1 mole of KBr is equivalent to 119 g
Therefore, the mass = 0.04025 ×  119  g = 4.79 g
6 0
4 years ago
Read 2 more answers
EXTRA POINTSSS 1. A solution at 25 degrees Celsius is 1.0 × 10–5 M H3O+. What is the concentration of OH– in this solution?
AlekseyPX

Answer:

Concentration of OH⁻:

1.0 × 10⁻⁹ M.

Explanation:

The following equilibrium goes on in aqueous solutions:

\text{H}_2\text{O}\;(l)\rightleftharpoons \text{H}^{+}\;(aq) + \text{OH}^{-}\;(aq).

The equilibrium constant for this reaction is called the self-ionization constant of water:

K_w = [\text{H}^{+}]\cdot[\text{OH}^{-}].

Note that water isn't part of this constant.

The value of K_w at 25 °C is 10^{-14}. How to memorize this value?

  • The pH of pure water at 25 °C is 7.
  • [\text{H}^{+}] = 10^{-\text{pH}} = 10^{-7}\;\text{mol}\cdot\text{dm}^{-3}
  • However, [\text{OH}^{-}] = [\text{H}^{+}]=10^{-7}\;\text{mol}\cdot\text{dm}^{-3} for pure water.
  • As a result, K_w = [\text{H}^{+}] \cdot[\text{OH}^{-}] = (10^{-7})^{2} = 10^{-14} at 25 °C.

Back to this question. [\text{H}^{+}] is given. 25 °C implies that K_w = 10^{-14}. As a result,

\displaystyle [\text{OH}^{-}] = \frac{K_w}{[\text{H}^{+}]} = \frac{10^{-14}}{1.0\times 10^{-5}} = 10^{-9} \;\text{mol}\cdot\text{dm}^{-3}.

8 0
4 years ago
Valeric acid, HC5H9O2 (Ka = 1.5 ✕ 10−5), is used in the manufacture of magnesium valerate, a nerve-calming agent. What is the hy
Studentka2010 [4]

Answer:

[H^+]=0.00332M

Explanation:

Hello,

In this case, considering the dissociation of valeric acid as:

HC_5H_9O_2 \rightleftharpoons C_5H_9O_2 ^-+H^+

Its corresponding law of mass action is:

Ka=\frac{[H^+][C_5H_9O_2^-]}{[HC_5H_9O_2]}

Now, by means of the change x due to dissociation, it becomes:

Ka=\frac{(x)(x)}{0.737-x}=1.5x10^{-5}

Solving for x we obtain:

x=0.00332M

Thus, since the concentration of hydronium equals x, the answer is:

[H^+]=x=0.00332M

Best regards.

7 0
3 years ago
What is the pH value of Potassium hydroxide
RSB [31]

Answer:

from 10-14

Explanation:

the pH of potassium hydroxide is extremely high and is a strong base although the exact value depends on the concentration of the base in water.

3 0
2 years ago
Read 2 more answers
The rate law for the decomposition of phosphine () is It takes 135. s for 1.00 M to decrease to 0.250 M. How much time is requir
vova2212 [387]

Answer:

189.71 secs

Explanation:

We know that decomposition is a first order reaction;

So;

ln[A] = ln[A]o - kt

But;

[A]o = 1.00 M

[A] = 0.250 M

t =135 s

Hence;

ln[A] -  ln[A]o = kt

k = ln[A] -  ln[A]o/t

k = ln(1) - ln(0.250)/135

k =0 - (-1.386)/135

k = 1.386/135

k= 0.01

So time taken now will be;

ln[A] -  ln[A]o = kt

t = ln[A] -  ln[A]o/k

t = ln (3) - ln(0.450)/0.01

t = 1.0986 - (-0.7985)/0.01

t = 1.0986 + 0.7985/0.01

t = 189.71 secs

8 0
3 years ago
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