The Equation of reaction
C + O2 === CO2
First Blank spot would be
---- 3.5moles of O2
2nd spot
Up.... 1mole of CO2
Down ---- 2moles of Oxygen atoms
3rd spot
Up... --- 22.4L of CO2(1mole of any gas at STP contains 22.4L)
Down---- 1mole of CO2
Final answer --- 3.5 x 1/2 x 22.4
=39.2L of CO2
Answer:
Clearly volume will INCREASE almost sevenfold, as we would expect if we reduce the pressure. Marilia E.K. The final volume of this gas will be 1.7L.
First things first carbon is quite common element here in Earth. But it is not all, right? Otherwise we would be built from other, more common elements. The thing is in carbon reactiveness. Also energy needed to create carbon chemical compounds isnt that big when compared to etc nitrogen. It can bind up to 4 different elements (atoms). Thanks to this can givesingle, both and triple bindings! Carbon can give away electrons or take them making his degree of oxidation consequently from -IV to +IV. All this vareity leads to vareity of bigger elements that will be created from carbon later- carbohydrates, proteins etc. As life needs vareity to adapt to different situations and climax only carbon therefore can provide this.
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Answer:</h3>
5.89%
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Explanation:</h3>
We are given;
- Mass of the solute, LiOH as 40.1 g
- Mass of the solvent, H₂O as 681 g
We are required to calculate the mass percent composition of solution;
- But; How do we calculate the mass percent composition of a solution?
- We use the formula;
- Mass composition of a solution = (Mass of solute/mass of solution) 100%
Mass Percent = (40.1 g/681 g)× 100%
= 5.888 %
= 5.89%
Therefore, the mass percent composition of the solution is 5.89%
Answer:
Both electrons of Mg should be transferred to one O.
Explanation:
This is because metals like to lose electrons whereas non metals like to gain electrons in an ionic compound. MgO is an ionic compounds. So Magnesium being a metal in group 2 of periodic table, it wants to donate 2 electrons to get to the octet rule, so it donates its electrons and oxygen accepts them to fill its octet rule.
