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3 years ago

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masha68 [24]3 years ago

5 0

Answer:

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Explanation:

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Copper sulfate is a blue solid that is used to control algae growth. Solutions of copper sulfate that come in contact with the s

True [87]

Answer:

185.49 grams of Zinc would react with 454g (1lb) of copper sulfate

Explanation:

Yo know the following balanced reaction:

CuSO₄(aq)+ Zn(s) →Cu(s) + ZnSO₄(aq)

You can see that by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents and products are part of the reaction:

CuSO₄: 1 mole
Zn: 1 mole
Cu: 1 mole
ZnSO₄: 1 mole

Being:

Cu: 63.54 g/mole
S: 32 g/mole
O: 16 g/mole
Zn: 65.37 g/mole

the molar mass of the compounds participating in the reaction is:

CuSO₄:63.54 g/mole + 32 g/mole + 4*16 g/mole= 159.54 g/mole ≅ 160 g/mole
Zn: 65.37 g/mole
Cu: 63.54 g/mole
ZnSO₄: 65.37 g/mole + 32 g/mole + 4*16 g/mole= 161.37 g/mole

Then, by stoichiometry of the reaction, the following amounts of mass of reagent and product participate in the reaction:

CuSO₄: 1 moles* 160 g/mole= 160 g
Zn: 1 mole* 65.37 g/mole= 65.37 g
Cu: 1 mole* 63.54 g/mole= 63.54 g
ZnSO₄: 1 mole* 161.37 g/mole= 161.37 g

Now you can apply the following rule of three: if 160 grams of CuSO₄ react with 65.37 grams of Zn by this reaction stoichiometry, 454 grams of CuSO₄ with how much mass of Zn will it react?

$mass of Zn=\frac{454 grams of CuSO_{4} *65.37 grams of Zn}{160 grams of CuSO_{4}}$

mass of Zn= 185.49 grams

<u><em>185.49 grams of Zinc would react with 454g (1lb) of copper sulfate</em></u>

4 0

3 years ago

describe how to put a food you enjoy such as hamburger pizza or muffin identify one physical change that takes place as this foo

Debora [2.8K]

One chemical change would be baking the muffin.
One physical change would be chopping the fruits to add to the mixture

7 0

3 years ago

An unknown gaseous substance has a density of 1.06 g/L at 31 °C and 371 torr. If the substance has the following percent composi

Anarel [89]

Answer:

C) C4H6 - Right answer

Explanation:

Let's combine the Ideal Gases Law with density to get the molecular formula for the unknown gas.

Density = mass / volume

1.06 g /L means that 1.06 grams of compound occupy 1 liter of volume.

P . V = n . R . T

Pressure in Torr must be converted to atm

760 Torr are 1 atm

371 Torr are __ (371 .1)/760 = 0.488 atm

0.488 atm . 1L = 1.06g/MM . 0.082 . 304K

(0.488 atm . 1L) / 0.082 . 304K = 1.06g/ MM

Mass / Molar mass = Moles → That's why the 1.06 g / MM

0.0195 mol = 1.06g / MM

1.06g/0.0195 mol = MM → 54.3 g/m

Now, let's use the composition

100 g of compound have 88.8 g of C

54.3 g of compound have ___ (54.3 . 88.8) /100 = 48 g of C

100 g of compound have 11.2 g of H

54.3 g of compound have __ (54.3 . 11.2)/100 = 6 g of H

48 g of C are included un 4 atoms

6 g of H are included in 6 atoms

4 0

3 years ago

What does it means when your boyfriend doesnt talk to you

d1i1m1o1n [39]

Either he’s busy, or he is just trying to ignore you.

Need more info tho

7 0

4 years ago

2Li + H2SO4=Li2SO4 + H2 How many liters of hydrogen gas, H2 at STP can be produced from 3.0 moles of Li? The molar volume of a g

Gemiola [76]

Answer:

volume of $H_2=33.6 litre$

Explanation:

Firstly balance the given chemical equation,

$2Li + H_2SO_4=Li_2SO_4 + H_2$

From the given balance equation it is clearly that,

2 mole of Li gives 1 mole of H2 gas

$2 mole Li$ ⇔ $1 mole H_2$

$1 mole Li$ ⇔ $0.5 mole H_2$

$3 mole Li$ ⇔ $1.5 mole H_2$

hence

3 mole of Li will give 1.5 mole H2 gas

therefore volume of gas produced from 3 mole Li at $STP = 1.5\times22.4 \frac{L}{mol}$

volume of H2=33.6 litre

7 0

3 years ago