Answer:
83°C
Explanation:
The following were obtained from the question:
M = 40g
C = 4.2J/g°C
T1 = 91°C
T2 =?
Q = 1300J
Q = MCΔT
ΔT = Q/CM
ΔT = 1300/(4.2x40)
ΔT = 8°C
But ΔT = T1 — T2 (since the reaction involves cooling)
ΔT = T1 — T2
8 = 91 — T2
Collect like terms
8 — 91 = —T2
— 83 = —T2
Multiply through by —1
T2 = 83°C
The final temperature is 83°C
The total mass of his mixture is 100,000 grams. (Answer A)
You multiply 1,000 grams of water by 100 to get 100,000 grams.
So the total mass of Victor's mixture is 100,000 grams
Answer:
55.95K
Explanation:
its obtained from Q=MCT where
Q-amount of heat
M-mass of water
C-specefic heat capacity of water
T-change in temperature
