The answer is A.) igneous rocks
-- We already know the rate of revolutions per time ...
it's 1 revolution per 0.065 sec. We just have to
unit-convert that to 'per minute'.
(1 rev / 0.065 sec) x (60 sec / min) = (1 x 60) / (0.065) = <em>923 RPM</em> (rounded)
_______________________________
-- 1 revolution = 2π radians
(2π rad) / (0.065 sec) = (2π / 0.065) = <em>96.66 rad/sec</em> (rounded)
Answer:
241 kPa
Explanation:
The ideal gas law states that:

where
p is the gas pressure
V is its volume
n is the number of moles
R is the gas constant
T is the absolute temperature of the gas
We can rewrite the equation as

For a fixed amount of gas, n is constant, so we can write

Therefore, for a gas which undergoes a transformation we have

where the labels 1 and 2 refer to the initial and final conditions of the gas.
For the sample of gas in this problem we have

So we can solve the formula for
, the final pressure:
