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Agata [3.3K]
3 years ago
13

Choose all the answers that apply.

Physics
1 answer:
Serhud [2]3 years ago
8 0
<span>According to Newton's first law of motion:

-- objects at rest will remain at rest unless acted upon by an outside force

-- objects in motion will remain in motion unless acted upon by an outside force


</span>
You might be interested in
If potential energy at point A is 12 joules, what is the potential energy at D?
Irina-Kira [14]

Answer:

In D: 3J

Explanation:

Potential energy: Ep=mgh where m is the mass, h altitude.

In point A: h=20cm=0.2m

Epa=12=0.2×mg. Thus mg=12/0.2=60N

For point D: hd=5cm=0.05m

Epd=mg×0.05=60×0.05=3J

5 0
3 years ago
Masses are stacked on top of the block until the top of the block is level with the waterline. This requires 20 g of mass. What
Kobotan [32]

Answer:

Mass of the wooden Block is 20g.

Explanation:

The buoyant force equation will be used here

Buoyant Force= ρ*g*1/2V Here density used is of water

m*g= ρ*g*1/2V

Simplifying the above equation

2m= ρ*V Eq-1

Also we know from the question that

ρ*V = m + 0.020 Eq-2 ( Density = (Mass+20g)/Volume )

Equating Eq-1 & Eq-2 we get

2m = m+0.020

m = 0.020kg

m = 20g

6 0
3 years ago
An student writes a bird that is divining for prey has speed of _ 10m/s what is wrong with the statement.
Anika [276]

Answer:

The description including its issue is summarized throughout the clarification portion below.

Explanation:

  • Speed would be a measurement of size. Which has only significance and therefore no path or guidance. Student says acceleration of -10m/s, therefore this assumption is incorrect because this same negative correlation indicates the path.
  • In reality, this same participant defined the speed (which seems to have two very different motion of an object).

4 0
3 years ago
In the formula Work=Force X Distance, what happens to the amount of work done if either Force or Distance is increased?
AfilCa [17]

Explanation:

If force or distance is increased, then amount of workdone will also increase.

6 0
3 years ago
A ball is thrown straight up from the edge of a 15 foot balcony with initial velocity 40 feet/sec. how high will the ball travel
NeTakaya
Hello
The initial height of the ball is S_i = 15~ft = 4.6~m, while the initial velocity is v_i = 40ft/s = 12.2~m/s.
This is a uniformly accelerated motion, where the acceleration is the gravitational acceleration: a=-9.8~m/s^2, where the negative sign means that the acceleration points downwards. 
We can proceed in two steps: 

1) First of all, we calculate the time the ball needs to reach the maximum height. At the point of maximum height, the velocity is zero: v_f = 0m/s. 
We can use the formula
a= \frac{v_f-v_i}{\Delta t}
To find the time:
\Delta t= \frac{v_f-v_i}{a} = 1.2 s

2) At this point, we can calculate the total height reached by the ball after this time, i.e. the maximum height:
S=S_i+v_i \Delta t+ \frac{1}{2} a (\Delta t)^2 =
= 4.6~m+(12.2~m/s)(1.2~s)+ \frac{1}{2}(-9.8~m/s^2)(1.2~s)^2 = 12.1~m
3 0
3 years ago
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