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3 years ago

Choose all the answers that apply.

1 answer:

8 0

<span>According to Newton's first law of motion:

-- objects at rest will remain at rest unless acted upon by an outside force

-- objects in motion will remain in motion unless acted upon by an outside force

</span>

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If potential energy at point A is 12 joules, what is the potential energy at D?

Irina-Kira [14]

Answer:

In D: 3J

Explanation:

Potential energy: Ep=mgh where m is the mass, h altitude.

In point A: h=20cm=0.2m

Epa=12=0.2×mg. Thus mg=12/0.2=60N

For point D: hd=5cm=0.05m

Epd=mg×0.05=60×0.05=3J

5 0

3 years ago

Masses are stacked on top of the block until the top of the block is level with the waterline. This requires 20 g of mass. What

Kobotan [32]

Answer:

Mass of the wooden Block is 20g.

Explanation:

The buoyant force equation will be used here

Buoyant Force= ρ*g*1/2V Here density used is of water

m*g= ρ*g*1/2V

Simplifying the above equation

2m= ρ*V Eq-1

Also we know from the question that

ρ*V = m + 0.020 Eq-2 ( Density = (Mass+20g)/Volume )

Equating Eq-1 & Eq-2 we get

2m = m+0.020

m = 0.020kg

m = 20g

6 0

3 years ago

An student writes a bird that is divining for prey has speed of _ 10m/s what is wrong with the statement.

Anika [276]

Answer:

The description including its issue is summarized throughout the clarification portion below.

Explanation:

Speed would be a measurement of size. Which has only significance and therefore no path or guidance. Student says acceleration of -10m/s, therefore this assumption is incorrect because this same negative correlation indicates the path.
In reality, this same participant defined the speed (which seems to have two very different motion of an object).

4 0

3 years ago

In the formula Work=Force X Distance, what happens to the amount of work done if either Force or Distance is increased?

AfilCa [17]

Explanation:

If force or distance is increased, then amount of workdone will also increase.

6 0

3 years ago

A ball is thrown straight up from the edge of a 15 foot balcony with initial velocity 40 feet/sec. how high will the ball travel

NeTakaya

Hello
The initial height of the ball is $S_i = 15~ft = 4.6~m$ , while the initial velocity is $v_i = 40ft/s = 12.2~m/s$ .
This is a uniformly accelerated motion, where the acceleration is the gravitational acceleration: $a=-9.8~m/s^2$ , where the negative sign means that the acceleration points downwards.
We can proceed in two steps:

1) First of all, we calculate the time the ball needs to reach the maximum height. At the point of maximum height, the velocity is zero: $v_f = 0m/s$ .
We can use the formula
$a= \frac{v_f-v_i}{\Delta t}$
To find the time:
$\Delta t= \frac{v_f-v_i}{a} = 1.2 s$

2) At this point, we can calculate the total height reached by the ball after this time, i.e. the maximum height:
$S=S_i+v_i \Delta t+ \frac{1}{2} a (\Delta t)^2 =$
$= 4.6~m+(12.2~m/s)(1.2~s)+ \frac{1}{2}(-9.8~m/s^2)(1.2~s)^2 = 12.1~m$

3 0

3 years ago