Answer:
<h2>0.05 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 0.025 × 2
We have the final answer as
<h3>0.05 N</h3>
Hope this helps you
Waning Gibbous would be the phase?
Answer: hello your questions lacks the required resistor values therefore i will provide a general answer using an example
answer : a) 14 ohms b) 0.86 amps c) 10.32 V
Explanation:
Assuming the resistors are : 3 ohms , 4 ohms and 5 ohms
Voltage source = 12V
<u>Assuming that the Resistors are in series </u>
<u>a) Determine Total resistance </u>
Req = R1 + R2 + R3
= 3 + 4 + 5 = 14 ohms
<u>b) Total current </u>
Ieq = V / Req
= 12 / 14 = 0.86 amps
<u>c) The Total Voltage over the entire system </u>
Vt = ∑ Voltage drops
= ( 0.86 * 3 ) + ( 0.86 * 4 ) + ( 0.86 * 5 )
= 10.32 V
According to Newton’s second law of motion, also know as the law of force and Accelerate , a force upon an object causes it to accelerate according to the formula net force = mass x acceleration
Answer:
v₂ = 7/ (0.5)= 14 m/s
Explanation:
Flow rate of the fluid
Flow rate is the amount of fluid that circulates through a section of the pipeline (pipe, pipeline, river, canal, ...) per unit of time.
The formula for calculated the flow rate is:
Q= v*A Formula (1)
Where :
Q is the Flow rate (m³/s)
A is the cross sectional area of a section of the pipe (m²)
v is the speed of the fluid in that section (m/s)
Equation of continuity
The volume flow rate Q for an incompressible fluid at any point along a pipe is the same as the volume flow rate at any other point along a pipe:
Q₁= Q₂
Data
A₁ = 2m² : cross sectional area 1
v₁ = 3.5 m/s : fluid speed through A₁
A₂ = 0.5 m² : cross sectional area 2
Calculation of the fluid speed through A₂
We aply the equation of continuity:
Q₁= Q₂
We aply the equation of Formula (1):
v₁*A₁= v₂*A₂
We replace data
(3.5)*(2)= v₂*(0.5)
7 = v₂*(0.5)
v₂ = 7/ (0.5)
v₂ = 14 m/s