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3 years ago

Increasing the two objects will cause the gravitational force between the objects to decrease.

2 answers:

8 0

Well first, I don't quite understand how you can "increase two objects".
I mean, you can increase their size, density, mass, weight, or cost,
but how do you "increase" the objects ?

If you were to, say, increase their mass ... or even the mass of only
one of them ... then the gravitational forces between the objects would
increase in strength.

So if you meant to say "increasing the mass of two objects", then
you've got yourself a nice genuine false statement there.

ELEN [110]3 years ago

4 0

This statement is false. Increasing the two objects' mass (I'm guessing) will actually increase their gravitational force. This is because of the equation:

$F_g = \frac{Gm_1m_2}{d^2}$

If the distance was increased, then the statement would be true, but since you are increasing mass, which is proportional to the Force of Gravity, you are in fact, increasing the gravitational force between the two objects.

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If a spaceship has a momentum of 30,000 kg-m/s to the right and a mass of

m_a_m_a [10]

Answer:

75m/s

Explanation:

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8 0

2 years ago

A soccer player is running upfield at 10m/s and comes to a stop in 3 seconds facing the same direction. What is his acceleration

Mekhanik [1.2K]

The players acceleration is 3.33 m/s/s

Acceleration= Velocity/Time

A =10/3

4 0

3 years ago

Read 2 more answers

If a proton is released at the equator and falls toward earth under the influence of gravity, the magnetic force on the proton w

pantera1 [17]

Positive positive side naturally because protons always move to positive side and electron always move to negative side

3 0

2 years ago

Henry, whose mass is 95 kg, stands on a bathroom scale in an elevator. The scale reads 830 N for the first 3.8 s after the eleva

Delicious77 [7]

Answer:

v= 4.0 m/s

Explanation:

When standing on the bathroom scale within the moving elevator, there are two forces acting on Henry's mass: Normal force and gravity.
Gravity is always downward, and normal force is perpendicular to the surface on which the mass is located (the bathroom scale), in upward direction.
Normal force, can adopt any value needed to match the acceleration of the mass, according to Newton's 2nd Law.
Gravity (which we call weight near the Earth's surface) can be calculated as follows:

$F_{g} = m*g = 95 kg * 9.8 m/s2 = 930 N (1)$

According to Newton's 2nd Law, it must be met the following condition:

$F_{net} = F_{g} -F_{n} = m*a\\ F_{net} = 930 N - 830 N = 100 N = 95 Kg * a$

As the gravity is larger than normal force, this means that the acceleration is downward, so, we choose this direction as the positive.

Solving for a, we get:

$a =\frac{F_{net} }{m} =\frac{100 N}{95 kg} = 1.05 m/s2$

We can find the speed after the first 3.8 s (assuming a is constant), applying the definition of acceleration as the rate of change of velocity:

$v_{f} = a* t = 1.05 m/s * 3.8 m/s = 4.0 m/s$

Now, if during the next 3.8 s, normal force is 930 N (same as the weight), this means that both forces are equal each other, so net force is 0.
According to Newton's 2nd Law, if net force is 0, the object is either or at rest, or moving at a constant speed.
As the elevator was moving, the only choice is that it is moving at a constant speed, the same that it had when the scale was read for the first time, i.e., 4 m/s downward.

3 0

3 years ago

A charge of +3.0 mC is distributed uniformly along the circumference of a circle with a radius of 20 cm. How much external energ

Marat540 [252]

Answer:

Work done = 4584.9 J

Explanation:

given: q1=3.0 mC = 3.0 × 10⁻³ C, r = 20 cm = 0.20 m, q1 = 34μC = 34 × 10⁻⁶ C

Solution:

Formula for the potential difference at the center of the circle

P.E = K × q1 q2 /r (Coulomb's constant k= 8.99 × 10⁹ N·m² / C²)

P.E = 8.99 × 10⁹ N·m² / C² × 3.0 × 10⁻³ C × 34 × 10⁻⁶ C / 0.20 m

P.E = 4584.9 J = Work done

3 0

3 years ago