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Lorico [155]
4 years ago
13

Increasing the two objects will cause the gravitational force between the objects to decrease.

Physics
2 answers:
melamori03 [73]4 years ago
8 0
Well first, I don't quite understand how you can "increase two objects".
I mean, you can increase their size, density, mass, weight, or cost,
but how do you "increase" the objects ?

If you were to, say, increase their mass ... or even the mass of only
one of them ... then the gravitational forces between the objects would
increase in strength.

So if you meant to say "increasing the mass of two objects", then
you've got yourself a nice genuine false statement there. 
ELEN [110]4 years ago
4 0
This statement is false. Increasing the two objects' mass (I'm guessing) will actually increase their gravitational force. This is because of the equation:

F_g =  \frac{Gm_1m_2}{d^2}

If the distance was increased, then the statement would be true, but since you are increasing mass, which is proportional to the Force of Gravity, you are in fact, increasing the gravitational force between the two objects.
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When you look at an object in a mirror, the image is:
podryga [215]

Answer:

When you place an object in front of a mirror, you see the same object in the mirror. This image that appears to be behind the mirror is called the image. The object is the source of the incident rays, and the image is formed by the reflected rays. An image formed by reflection may be real or virtual.

7 0
3 years ago
Which of these is not shared by bohrs model and the modern atomic model?
KonstantinChe [14]

Answer:

D. both have electrons that orbit the atomic nucleus in a simaler way

Explanation:

the bohrs model electrons orbit in a circular pattern were as the modern atomic model orbit in every which way

3 0
3 years ago
HELP ASAP PLEEEEES
matrenka [14]

Explanation:

33. The 1.5kg owl is now soaring at 20m/s. What is the owl’s KE?

a. Step 1: Formula <u>½mv²</u>

b. Step 2: Data m = <u>1</u><u>.</u><u>5</u><u> </u><u>kg</u>, v = <u>2</u><u>0</u><u> </u><u>m</u><u>/</u><u>s</u>

c. Step 3: Solve

KE = (1/2)(<u>1</u><u>.</u><u>5</u>)(<u>2</u><u>0</u>)² = <u>3</u><u>0</u><u>0</u><u> </u><u>J</u>

6 0
3 years ago
A 7.5 nC point charge and a - 2.9 nC point charge are 3.2 cm apart. What is the electric field strength at the midpoint between
Oduvanchick [21]

Answer:

Net electric field, E_{net}=91406.24\ N/C

Explanation:

Given that,

Charge 1, q_1=7.5\ nC=7.5\times 10^{-9}\ C

Charge 2, q_2=-2.9\ nC=-2.9\times 10^{-9}\ C

distance, d = 3.2 cm = 0.032 m

Electric field due to charge 1 is given by :

E_1=\dfrac{kq_1}{r^2}

E_1=\dfrac{9\times 10^9\times 7.5\times 10^{-9}}{(0.032)^2}

E_1=65917.96\ N/C

Electric field due to charge 2 is given by :

E_2=\dfrac{kq_2}{r^2}

E_2=\dfrac{9\times 10^9\times 2.9\times 10^{-9}}{(0.032)^2}

E_2=25488.28\ N/C

The point charges have opposite charge. So, the net electric field is given by the sum of electric field due to both charges as :

E_{net}=E_1+E_2

E_{net}=65917.96+25488.28

E_{net}=91406.24\ N/C

So, the electric field strength at the midpoint between the two charges is 91406.24 N/C. Hence, this is the required solution.

3 0
4 years ago
A beach ball moving with a speed of 1.31 m/s rolls off a pier and hits the water 0.88 m from the end of the pier
slavikrds [6]
So what is the main question? I Need to know what the main question is to solve it.
5 0
4 years ago
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