What value of v is a solution to this equation? 4v–15=9 u = -7 or u = 0
1 answer:
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Answer:
Option B can be quadratic.
Step-by-step explanation:
Take a look at the data.
A quadratic equation is of the form ,
,
where, a,b,c are constants.
<em>To find an unknown equation of 3 variables,</em>
<em>we need 3 points lying on the equation.</em>
here they have given, 5 points, meaning all should lie on the curve.
<em>For first option,</em> inserting first 3 points to find equation, we get equation as,
, but the rest points don't satisfy the curve.
So first option is not quadratic.
Similarly, it can be shown that option C and D are also not quadratic.
While, in option B, it is clear that for every y, x is y squared,
, thus quadratic in nature.