Answer:
The compound is Na2CO3
Explanation:
A flame test of a colorless solution gives a bright yellow color. The yellow color shows the presence of Sodium.
NaX + AgNO3 → AgX + NaNO3
When reacted with AgNO3 a white precipitate.
AgX + HNO3 → AgNO3 + H2O + CO2
A white precipitate will be formed when AgNO3 reacts with Sodium Chloride (NaCl) or Sodium carbonate(Na2CO3). (Also NaF, Na3PO4 are possible).
When HCL is added to the unknown solution, bubbles form.
Forming bubbles means that there is formed CO2 (and H20)
Na2X + 2HCl → 2NaCl + H2O + CO2
To form CO2 there is carbon needed
This shows that X is CO3 and the compound is Na2CO3
<u>To control:</u>
Na2CO3 + AgNO3 → Ag2CO3 + NaNO3
⇒Ag2Co3 is the white precipitate formed
This precipitate Ag2CO3 + HNO3 will disolve in AgNO3, CO2 and H2O
When Na2CO3 reacts with HCl there is formed NaCL together with bubbles ( which is CO2 and H2O).
The compound is Na2CO3
