I think the answer is false
Explanation: In IUPAC, E-Z convention is given for describing the cis - trans notation to the isomers. According to CIP rule, the groups on the doubly bonded carbon atoms are given priorities based on the the atomic masses of first connected atom.
If the highest priority groups are on the same side, it is known as Z-form and if the highest priority groups are on opposite side, it is known as E-form.
We are given (Z)-3-bromo-6-methyl-2-heptene, in this the highest priority groups are bromine on one side and methyl- group on another side.
The structure is provided in the image below.
Answer:the initial composition of the reactants is
40cm^3 of CH4
40cm^3of H2
100cm^3 of H2O
Explanation:
Balanced reaction is
CH4 +H2+5/2O2______
CO2 +3H2O
Excess KOH at room temperature absorbs CO2 whose volume is given by 40cm^3 i.e the volume by which the solution decreases
So using Gay lussac combining ratio which states that gases combine in volumes that are in simple ratio to each other if gases.
Since CO2 in the equation is 1 mole
Means 1mole represent 40cm^3
So CH4:H2:O2 are in ratio of 1:1:5/2=(40:40:100)cm^3 respectively.
Answer:
Few important points related to
reaction:
1.
is a one-step reaction that follows second order kinetics.
2. In
reaction, a transition state is formed in situ.
3. Strong nucleophiles like
are used in case of bi-molecular nucleophilic substitution reaction.
Ethyl acetate can be prepared by a second-order nucleophilic substitution reaction between acetic acid and ethyl bromide.
The reaction between acetic acid and ethyl bromide is drawn below:
Answer:
mass O2 = 222.5 g
Explanation:
- %wt = ((mass compound)/(mass sln))×100
balance reaction:
∴ %wt H2 = 11 % = ((mass H2)/(mass H2O))×100
∴ %wt O2 = 89 % = ((mass O2)/(mass H2O))×100
∴ mass H2O 250 g
⇒ mass O2 = (0.89)(250 g)
⇒ mass O2 = 222.5 g