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solong [7]
3 years ago
13

Lindsay has 4 1/2 *(four and one half) cups of rice. She uses 3/4 (three-fourths) of the rice to make sushi rolls for dinner. Sh

e uses the rest of the rice to make rice pudding for dessert. How much rice does Lindsay use for the rice pudding?
Mathematics
1 answer:
liubo4ka [24]3 years ago
5 0

Answer:

3 3/4 cups

Step-by-step explanation:

4 2/4 minus 3/4 (taking away 2/4, then 1/4) would leave you with 3 3/4

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In this graph, the y-intercept of the line is( )
Yuliya22 [10]

Answer:

Y Intercept= -3

Equation= y=3x-3

Step-by-step explanation:

5 0
4 years ago
How do you do _+-5=-13
GalinKa [24]
First make the dash an x. Then move over to the other side of the = so it looks like this:
-5=-13-x
You take -13 to the other side of the equal sign so it looks like this:
-5+13=-x
Then:
8=-x or x=-8
Hopefully that makes sense.
5 0
4 years ago
Read 2 more answers
Assume that it costs Apple approximately E(x) 25,600 + 100x + 0.012 dollars to manufacture x 32GB iPods in a day. (a) The averag
uranmaximum [27]

Answer:

(a)C'(x)=\dfrac{x^2-2560000}{x^2}

(b)x=1600, Minimum Average Cost Per iPod=$132

(c)C''(x)=\dfrac{5120000}{x^3}

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

Step-by-step explanation:

Given that it costs Apple approximately $ C(x) to manufacture x 32GB iPods in a day, where:

C(x)=25,600+100x+0.01x^2

(a)The average cost per iPod when they manufacture x iPods in a day is given by:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}

The average cost per iPod is therefore:

C'(x)=\dfrac{x^2-2560000}{x^2}

(b)To minimize average cost of x iPods per day, we set the average cost per iPod=0 and solve for x.

C'(x)=\dfrac{x^2-2560000}{x^2}=0\\x^2-2560000=0\\x^2=2560000\\x=\sqrt{2560000}=1600

The resulting minimum average cost (at x=1600) is given as:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}\\\dfrac{25,600+100(1600)+0.01(1600)^2}{1600}\\=\$132

<u>Second derivative test</u>

(c)The answer above is a critical point for the average cost function. To show it is a minimum, we calculate the second derivative of the average cost function.

C''(x)=\dfrac{5120000}{x^3}

At the critical point,  x=1600

C''(1600)=\dfrac{5120000}{1600^3}=0.00125

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

3 0
3 years ago
Largest value 5/9,2/3,11/8
Dima020 [189]
Answer: 11/8

11/8= 1 3/8

1 3/8 > 2/3
6 0
2 years ago
4 times a number cubed
sergij07 [2.7K]

Answer:

(4n)^3

Step-by-step explanation:

Let n = number

4 times a number

4n

Cubed

(4n)^3

3 0
4 years ago
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