Answer:
-56/9
Step-by-step explanation:
Let p and q be the roots of the equation.
So, here's how we're gonna work it out:
Vieta's formulas give us the sum and the product of the roots of a quadratic equation. Using them we obtain:
- p + q = -b / a = - 4 / 3
- p × q = c / a = 12 / 3 = 4
Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer:
7.4
Step-by-step explanation:
Gud luck on the rest of your school work :)
The answer is option B. In the distributive property you need to multiply the constant that is outside of the parenthesis, with the terms that are inside :)
