All categories

3 years ago

The ticket for ice hockey match was £14.50. the price has increased by 7%.

Mathematics

2 answers:

Serjik [45]3 years ago

7 0

(14.50×7)/100 + 14.50

Anna35 [415]3 years ago

6 0

Initial price of ticket = 14.50

Increased % = 7

So, prize after increment, 14.50 + (14.50*7)/100

=14.50 + 1.015 = (currency) 15.515.

You might be interested in

Use your understanding of the symmetry of the sine and cosine functions to determine the value of tan(−theta) for all

Dmitriy789 [7]

Answer:

$tan(-\theta)=-tan\theta$

Odd function

Step-by-step explanation:

We are given that

$tan(-\theta)$

We have to determine the value of $tan(-\theta)$ and find tangent function is odd,even or neither.

$tan(-\theta)=\frac{sin(-\theta)}{cos(-\theta)}$

$tan\theta=\frac{sin\theta}{cos\theta}$

We know that

$sin(-\theta)=-sin\theta$

$cos(-\theta)=cos\theta$

By using identities

Then, we get

$tan(-\theta)=\frac{-sin\theta}{cos\theta}=-tan\theta$

$tan(-\theta)=-tan\theta$

Odd function: If $f(-x)=-f(x)$

Even function:If $f(-x)=f(x)$

$tan(-\theta)=-tan\theta$

Therefore, function is an odd function.

7 0

3 years ago

PLLLLEEEEEEAAASSSSSSSSEEEE

mrs_skeptik [129]

Given:

Line a passes through (2, 10) and (4, 13).

Line b passes through (4, 9) and (6, 12).

Line c passes through (2, 10) and (4, 9).

To find:

Which of the lines, if any are perpendicular.

Solution:

If a line passes through two points, then the slope of line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Line a passes through (2, 10) and (4, 13). So, slope of this line is

$m_a=\dfrac{13-10}{4-2}=\dfrac{3}{2}$

Line b passes through (4, 9) and (6, 12). So, slope of this line is

$m_b=\dfrac{12-9}{6-4}=\dfrac{3}{2}$

Line c passes through (2, 10) and (4,9). So, slope of this line is

$m_c=\dfrac{9-10}{4-2}=\dfrac{-1}{2}$

Product of slopes of to perpendicular lines is -1.

$m_a\cdot m_b=\dfrac{3}{2}\times \dfrac{3}{2}=\dfrac{9}{4}\neq -1$

$m_b\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

$m_a\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

Therefore, any of these lines are not perpendicular to each other.

8 0

3 years ago

Mcd de 120 , 160 , 180 , 200 paso por paso (el que responda le doy corona)

olga55 [171]

Answer:

The Highest Common Factor is 20

Step-by-step explanation:

Aquí le mostraremos paso a paso como hallar el Máximo Común Divisor de 120 y 180. (mcd de 120 y 180) Paso 1: Creamos una lista de todos los divisores de 120, que incluye 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, y 120. Paso 2: Siguiente, creamos una lista de todos los divisores de 180, que incluye 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, y 180. Paso 3: Finalmente, comparamos las listas de Paso 1 y Paso 2 y hallamos que el mayor número que tienen en común es 60. Esto significa que el Máximo Común Divisor de 120 y 180 es 60. MCD de 120 y 180 = 60

4 0

3 years ago

Please hurry

disa [49]

Answer: x

Step-by-step explanation:

6 0

3 years ago

DUE TODAY BEING HOEST PLs HELLP :(

Triss [41]

The answer is 3:9 or 1:3

3 0

3 years ago

Read 2 more answers