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3 years ago

Which statement refers to convection?

Chemistry

2 answers:

photoshop1234 [79]3 years ago

8 0

Answer:

Your answer is D

Explanation:

Nonamiya [84]3 years ago

4 0

Warm air rises and takes heat with it; eventually cools and sinks

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ACCORDING TO THE LAW OF CONSERVATION OF MASS,WHAT SHOULD THE PRODUCT SIDE OF THIS SINGLE REPLACEMENT REACTION LOOK LIKE? Zn+2

statuscvo [17]

The correct answer is C because Zn+2HCl= ZnCl2+H

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4 years ago

Inside the room the air is often warmer near the ceiling than near the floor. Which of the following accounts for the difference

Rudiy27

The correct answer would be C. Convection, which describes that heat rises.

3 0

3 years ago

Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 17. g of octane is mi

Lisa [10]

Answer: 52.8 g of $CO_2$

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

a) moles of octane

$\text{Number of moles}=\frac{17.0g}{114g/mol}=0.150moles$

b) moles of oxygen

$\text{Number of moles}=\frac{93.0g}{32g/mol}=2.91moles$

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

According to stoichiometry :

2 moles of $C_8H_{18}$ require 25 moles of $O_2$

Thus 0.150 moles of $C_8H_{18}$ require= $\frac{25}{2}\times 0.150=1.875moles$ of $O_2$

Thus $C_8H_{18}$ is the limiting reagent as it limits the formation of product and $O_2$ is the excess reagent.

As 2 moles of $C_8H_{18}$ give = 16 moles of $CO_2$

Thus 0.150 moles of $C_8H_{18}$ give = $\frac{16}{2}\times 0.150=1.2moles$ of $CO_2$

Mass of $CO_2=moles\times {\text {Molar mass}}=1.2moles\times 44g/mol=52.8g$

Thus 52.8 g of $CO_2$ will be produced from the given masses of both reactants.

8 0

3 years ago

100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

9966 [12]

The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are $0.38\times 10^{-5}$ and $18.62\times 10^{-5}g$ respectively

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in ml

$3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}$

$n=0.38\times 10^{-5}$

n = moles of $NaCN$ = $\frac{\text {given mass}}{\text {Molar mass}}$

$0.38\times 10^{-5}=\frac{x}{49g/mol}$

$x=18.62\times 10^{-5}g$

Thus the number of moles and the mass of the solute are $0.38\times 10^{-5}$ and $18.62\times 10^{-5}g$ respectively

6 0

3 years ago

If 5 moles of KCIO3 react completely how many moles of KCI will firm

Lubov Fominskaja [6]

With what KClO3 reacts with if it is by temperature
2KClO3===》KCl + KClO + O2

4 0

3 years ago