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ludmilkaskok [199]
3 years ago
6

Which of the following is the most plausible explanation for the fact that the saponification of the triacylglycerol in the pass

age resulted in four different fatty acid salts?
a. The triacylglycerol molecule consisted of four different fatty acid units.
b. Glycerol was transformed into a fatty acid salt under the reaction conditions.
c. One of the fatty acid salts was unsaturated, and it completely isomerized under the reaction conditions.
d. One of the fatty acid salts was unsaturated, and a small percentage isomerized under the reaction conditions.
Chemistry
1 answer:
aalyn [17]3 years ago
8 0

Answer: The correct option is C (One of the fatty acid salts was unsaturated, and it completely isomerized under the reaction conditions).

Explanation:

Fats and oils belongs to a general group of compounds known as lipids. Fatty acids are weak acid and are divided into two:

--> Saturated fatty acids: These have NO double bonds in their hydrocarbon chain, and

--> Unsaturated fatty acids: These have one or more double bonds in their hydrocarbon chain.

SAPONIFICATION is defined as the process by which fats and oil is hydrolyzed with caustic alkali to yield propane-1,2,3-triol and the corresponding sodium salt of the component fatty acids. During this process, One hydroxide ion is required to hydrolyze one ester linkage of a triacylglycerol molecule. Because there are three ester linkages in a triacylglycerol, three equivalents of sodium hydroxide will be needed to completely saponify the triacylglycerol. This explains the reason why saponification of the triacylglycerol iresulted in four different fatty acid salts.

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Answer:

D. The presence of a base catalyst.

E. The presence of an acid catalyst. and

F. The presence of heat.

Explanation:

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3 years ago
A certain chemical reaction releases 31.0 kj/g of heat for each gram of reactant consumed. How can you calculate what mass of re
Aleksandr-060686 [28]

Answer:

See explanation.

Explanation:

Hello!

In this case, since we know the heat of reaction per gram of reactant and we should know the total energy of reaction, but it is not there, we are going to assume it is 1200 J as usual in these problems, so you can change it to whatever your given heat is.

In such a way, we set up the math as shown below:

m= 1200J*\frac{1kJ}{1000J}*\frac{1g}{31.0kJ}

Which results:

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7 0
3 years ago
Pharmacists sometimes measure medicines in the unit of "grains," where 1 gr = 65 mg. The label on a bottle of aspirin reads "Asp
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Answer:

325mg of Aspririn

Explanation:

First you should note the information that the problem gives you:

- The bottle of Aspirin has 5gr (grains)

- 1gr(grain) = 65mg (miligrams)

Also, the problem is asking about how many aspirin are in 5 gr (grains), so you should use a conversion factor, as follows:

-First you should put the quantity you need to convert:

5grAspirin

-Then you write the denominator of the conversion factor that must have the same units that you want to convert, in this case gr:

5grAspirin*\frac{}{1grAspirin}

-Then you write the numerator with the units that you want to obtain and the numerical equivalence between the units, in this case:

5grAspirin*\frac{65mgAspririn}{1grAspirin}

-Finally you multiply numerators and divide by denominators:

5grAspirin*\frac{65mgAspririn}{1grAspirin}=325mgAspririn

8 0
3 years ago
Which of the following is a biotic of an ecosystem a rock air grass climate
Zigmanuir [339]
Grass is biotic- living.

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3 years ago
Determine whether a precipitate will form when 0.96g of Na2CO3 is combined with 0.20g BaBr2 in a 10 L solution.
Mashcka [7]

Answer:

Qsp > Ksp, BaCO3 will precipitate

Explanation:

The equation of the reaction is;

Na2CO3 + BaBr2 -------> 2NaBr + BaCO3

Since BaCO3 may form a precipitate we can determine the Qsp of the system.

Number of moles of Na2CO3 = 0.96g/106 g/mol = 9.1 * 10^-3 moles

concentration of NaCO3 = number of moles/volume of solution = 9.1 * 10^-3 moles/10 L = 9.1 * 10^-4 M

Number of moles of BaBr2 = 0.20g/297 g/mol = 6.7 * 10^-4 moles

concentration of BaBr2 = 6.7 * 10^-4 moles/10 L = 6.7 * 10^-5 M

Hence;

[Ba^2+] = 6.7 * 10^-5 M

[CO3^2-] = 9.1 * 10^-4 M

Qsp = [6.7 * 10^-5] [9.1 * 10^-4]

Qsp = 6.1 * 10^-8

But, Ksp for BaCO3 is 5.1*10^-9.

Since Qsp > Ksp, BaCO3 will precipitate

3 0
3 years ago
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