Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Step-by-step explanation:
X + Y = -3
X + 3x +5 = -3
X=-2
X+Y=-3
Y=-3+2
Y=-1
Yes they are equal because lets say the rectangle's area is 14 and if you divide 14 into 2 it will be 7 and 7+7=14
Answer/Step-by-step explanation:
2x-5y=9
Add 5y to both sides of the equation.
2x=9+5y
Divide each term by 2 and simplify.
Divide each term in 2x=9+5y by 2

Cancel the common factor of 2.
Divide x by 1.

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3x+4y=2
Add 4y to both sides of the equation
3x=2+4y
Divide each term by 3 and simplify.
Divide each term in 3x=2+4y by 3.

Cancel the common factor of 3.
Divide x by 1.


Keeping in mind that an hour is 60 minutes.