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3 years ago

Which expression is equal to (3m)^2/5

1 answer:

5 0

ANSWER

The correct answer is

$\sqrt[5]{9 {m}^{2}}$

EXPLANATION

The given expression is

${(3m)}^{ \frac{2}{5} }$

We can rewrite the exponent as

${(3m)}^{ \frac{1}{5} \times 2 }$

Or

$({(3m)}^{ 2 } )^{ \frac{1}{5} }$

We evaluate the inner expression to obtain,

$(9 {m}^{2} )^{ \frac{1}{5} }$

We then rewrite as,

$\sqrt[5]{9 {m}^{2}}$

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What is true about a rhombus and square?

Genrish500 [490]

Answer:

B. all of these are true

Step-by-step explanation:

The Square is a rhombus because all the sides of a square are equal in length. Even, the diagonals of both square and rhombus are perpendicular to each other and bisect the opposite angles. Therefore, we can say the square is a rhombus.

Hope this helped!!

5 0

3 years ago

19.25 divided by 3.5

Colt1911 [192]

Answer:

It would be 5.5

for a better understanding, look it up on google

4 0

3 years ago

For a ride on a rental scooter, Deon paid an $8 fee to start the scooter plus 6 cents per minute of the ride. The total bill for

faltersainse [42]

Answer:

66 minutes

Step-by-step explanation:

11.96 - 8 =3.96

Every 10 minutes Deon pays 60 cents because 6 times 10 = 60 and every 6 minutes Deon is paying 36 cents

10 min = 60 cents

20 min = $1.20

40 min = $2.40

50 min = $3.00

60 min = $3.60

6 min = 36 cents

Then you do 3.60 + 36 which equals $3.96

How to figure how the minutes is just 60 + 6 = 66 minutes

7 0

2 years ago

Please someone help me to prove this..

Pachacha [2.7K]

Answer: see proof below

<u>Step-by-step explanation:</u>

Use the following Sum to Product Identities:

$\sin x+\sin y=2\sin \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\sin x-\sin y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=-2\sin \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)$

<u>Proof LHS → RHS</u>

$\text{LHS:}\qquad \qquad \qquad \dfrac{\sin 5-\sin 15+\sin 25 - \sin 35}{\cos 5-\cos 15- \cos 25 + \cos 35}$

$\text{Reqroup:}\qquad \qquad \qquad \dfrac{(\sin 25+\sin 5)-(\sin 35 + \sin 15)}{(\cos 35+\cos 5)-(\cos 25 + \cos 15)}$

$\text{Sum to Product:}\quad \dfrac{2\sin \bigg(\dfrac{25+5}{2}\bigg)\cos \bigg(\dfrac{25-5}{2}\bigg)-2\sin \bigg(\dfrac{35+15}{2}\bigg)\cos \bigg(\dfrac{35-15}{2}\bigg)}{2\cos \bigg(\dfrac{25+15}{2}\bigg)\cos \bigg(\dfrac{25-15}{2}\bigg)-2\cos \bigg(\dfrac{35+5}{2}\bigg)\cos \bigg(\dfrac{35-5}{2}\bigg)}$ $\text{Simplify:}\qquad \qquad \dfrac{2\sin 15\cos 10-2\sin 25\cos 10}{2\cos 20\cos 15-2\cos 20\cos 5}$

$\text{Factor:}\qquad \qquad \dfrac{2\cos 10(\sin 15-\sin 25)}{2\cos 20(\cos 15-\cos 5)}$

$\text{Sum to Product:}\qquad \dfrac{\cos 10\bigg[2\cos \bigg(\dfrac{15+25}{2}\bigg)\sin \bigg(\dfrac{15-25}{2}\bigg)\bigg]}{\cos 20\bigg[-2\sin \bigg(\dfrac{15+5}{2}\bigg)\sin \bigg(\dfrac{15-5}{2}\bigg)\bigg]}$

$\text{Simplify:}\qquad \qquad \dfrac{\cos 10[2\cos 20\sin (-5)]}{\cos 20[-2\sin 10\sin 5]}\\\\\\.\qquad \qquad \qquad =\dfrac{-2\cos10 \cos 20 \sin 5}{-2\sin 10 \cos 20 \sin 5}\\\\\\.\qquad \qquad \qquad =\dfrac{\cos 10}{\sin 10}\\\\\\.\qquad \qquad \qquad =\cot 10$