Answer:


And we can find the limits in order to consider values as significantly low and high like this:


Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
For this case we can consider a value to be significantly low if we have that the z score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is higher tor equal to 2.
For this case we have the mean and the deviation given:


And we can find the limits in order to consider values as significantly low and high like this:


Answer:
$1.30
Step-by-step explanation:
Let x = the cost of the pencil
Let x + .80 = the cost of the pen
Let 4(x + .80) = the cost of the binder
x + x + .80 + 4(x + .80) = 11.80
2x + .80 + 4x + 3.20 = 11.80
6x + 4.00 = 11.80
6x = 7.80
x = $1.30
x + .80 = $2.10
4(x + .80) = $8.40
Answer:

Step-by-step explanation:
Whe have the function 
To solve this equation we must factor.
To factor, we need to find the points where the function is equal to zero. So we use the quadratic formula

Where:
a = 3
b = -6
c = 2
Then

finally the correct answer is 
We have
f(x)=<span>−x</span>²<span>+ 5x + 6
g(x)=</span><span>3x − 2
we know that
f(x)=g(x)
the solution is the intersection both graphs
using a graph tool
see the attached figure
the solution are the points(4,10)and(-2,-8)</span>
It’s funny cause I have a friend named Rashawn
But y intercept would be 550 then multiply 8 by 6to get 48
So your answer should be $598 in 6 years