When you buy a new car it is a depreciating asset. Which means the moment you purchase your car it begins losing value. If you

Mathematics

1 answer:

Arturiano [62]2 years ago

4 0

I can't see the graph but I'll try anyway

Answer:

x y

0 $20,000

1 $18,000

2 $16,200

3 $14,580

4 $13,122

5 $11,809.80

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Help needed on this composition math problem

Marrrta [24]

Given that f(x) = x/(x - 3) and g(x) = 1/x and the application of function operators, f ° g (x) = 1/(1 - 3 · x) and the domain of the resulting function is any real number except x = 1/3.

<h3>How to analyze a composed function</h3>

Let be f and g functions. Composition is a binary function operation where the variable of the former function (f) is substituted by the latter function (g). If we know that f(x) = x/(x - 3) and g(x) = 1/x, then the composed function is:

$f\,\circ\,g \,(x) = \frac{\frac{1}{x} }{\frac{1}{x}-3}$

$f\,\circ\,g\,(x) = \frac{\frac{1}{x} }{\frac{1-3\cdot x}{x} }$

$f\,\circ\,g\,(x) = \frac{1}{1-3\cdot x}$

The domain of the function is the set of x-values such that f ° g (x) exists. In the case of rational functions of the form p(x)/q(x), the domain is the set of x-values such that q(x) ≠ 0. Thus, the domain of f ° g (x) is $\mathbb{R} - \{\frac{1}{3} \}$ .

To learn more on composed functions: brainly.com/question/12158468

#SPJ1

3 0

1 year ago

What is the derivative of the function below?

11111nata11111 [884]

$g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}$