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tigry1 [53]
2 years ago
15

The cost of holding a children's birthday party at a rollerskating rink is a function of n, the number of people in the party. T

he cost function C can be represented with this set of rules:
Question: How much will it cost with 20 people?
Mathematics
1 answer:
Bas_tet [7]2 years ago
4 0

Answer: It would cost $150 for a party of 9 people and it would cost $260 for 20 people

Step-by-step explanation:

The number 9 falls in between 0<n<_ 12 so the cost is 150

The number 20 falls in between 12<n<_ 20 so the cost is 260

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What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
2 years ago
Can you explain it and help me out please​
Anarel [89]

Answer:

c.

Step-by-step explanation:

2x² - 4x - 3 = 0

x= \frac{-b+/-\sqrt{b^{2}-4ac} }{2a} \\\\x= \frac{-(-4)+/-\sqrt{(-4)^{2}-4*2*(-3)} }{2*2} \\\\x= \frac{4+/-\sqrt{16+24} }{4} \\\\x= \frac{4+/-\sqrt{40} }{4} = \frac{4+/-2\sqrt{10} }{4}=\frac{2+/-\sqrt{10} }{2}

6 0
3 years ago
Read 2 more answers
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PilotLPTM [1.2K]

Answer:

The difference is 4–3. If you want the difference between 3 and -4, then the difference is 7.

Step-by-step explanation:

6 0
3 years ago
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borishaifa [10]

Answer:The answer is given by :

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Step-by-step explanation:

5 0
3 years ago
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