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alexdok [17]
3 years ago
7

Increase 40 by 1/2 I need help, im bad at mathematics.

Mathematics
1 answer:
Bess [88]3 years ago
6 0

Answer:

The answer is :60

Step-by-step explanation:

Hmmmm...... because

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What is the equation, in point-slope form, for a line that goes through (2, -6) and has
sdas [7]
Answer: D

Explanation:

Point slope form:

(y - y1) = m(x - x1)

Coordinate given = (2,-6)
Slope = 3/5

Thus:
(y -(-6)) = 3/5(x - 2)
y + 6 = 3/5(x - 2)
6 0
3 years ago
The scale on a map is 1 :50000.
mestny [16]

Answer:

The actual area of the field in square kilometers is 30000000 km^2

Step-by-step explanation:

Scale : 1 cm = 50000 km

Area of field on map = 1.2 cm^2

Now , 1 cm = 5000 km

1 cm^2 = (5000 km)^2

We are supposed to find the actual area of the field in square kilometers.

So, the actual area of the field in sq. km =1.2 \times  (5000)^2

Actual area of the field in sq. km =30000000 km^2

Hence the actual area of the field in square kilometers is 30000000 km^2

6 0
3 years ago
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
4 years ago
Please please help me
zhuklara [117]

Answer:

first one

Step-by-step explanation:

yes, the interval does increase at -2. however, you can see it decreases again but starts rising up again at the interval 1.

3 0
4 years ago
Need help find the missing term
Lerok [7]
Let me show u one in detail.

First we have to find the common ratio. We do this by dividing the second term by the first term.

ur first problem...
12/3 = 4...so the common ratio is 4

now we use the formula
an = a1 * r^(n-1)
n = term u want to find = 15
a1 = first term = 3
r = common ratio = 4
now we sub
a15 = 3 * 4^(15 - 1)
a15 = 3 * 4^14
a15 = 3 * 268435456
a15 = 805,306,368 <== ur 15th term

thats all there is to it...and, of course, u can always look on the internet for a geometric sequence calculator...to check urself...lol
7 0
4 years ago
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