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3 years ago

What is the 22nd term of the arithmetic sequence 12 , 17 , 22 , 27 , .... , .... , ....

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

5 0

Answer: 117

Step-by-step explanation:

Formula for arithmetic sequence is:

= a + (n - 1)d

22nd term = a + (n - 1)d

= a + (22 - 1)d = a + 21d

where, a = 12

d = 17 - 12 = 5.

Therefore, 22nd term will be:

= a + 21d

= 12 + 21(5)

= 12 + 105

= 117

The 22nd term is 117

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AfilCa [17]

Answer : w = (-36)
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3 years ago

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If the area of the rectangle below is 36 square yards, what is the length of the missing side? Don’t forget to include the unit

Vitek1552 [10]

Answer: wheres the picture

Step-by-step explanation:

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3 years ago

Th<br> Write an<br> explicit formula for<br> ans<br> then<br> term of the sequence 40,50,60, ....

kenny6666 [7]

<h3>Answer: $a_n = 10n+30$ </h3>

n starts at 1, and n is a positive whole number (1,2,3,...)

======================================================

Explanation:

The sequence is arithmetic with first term 40 and common difference 10. Meaning we add 10 to each term to get the next one.

--------

a1 = 40 = first term

d = 10 = common difference

$a_n = a_1 + d(n-1)\\\\a_n = 40 + 10(n-1)\\\\a_n = 40 + 10n-10\\\\a_n = 10n + 30\\\\$

is the general nth term of this arithmetic sequence

Plug in n = 1 and you should get $a_1 = 40$

Plug in n = 2 and you should get $a_2 = 50$

and so on

6 0

4 years ago

Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student

AysviL [449]

Answer:

The mean calculated for this case is $\bar X=584$

And the 95% confidence interval is given by:

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=584$

The sample deviation calculated $s=86.776$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that $t_{\alpha/2}=2.776$