<span>Which of the following is the solution set of the equation
10(x^2+1/x^20)-63(x-1/x)=52=0
I think you type wrongly the equation:
It is : </span><span>10(x^2+1/x^2)-63(x-1/x)+52=0
We know: x</span>²+1/x²=(x-1/x)²+2, pose x-1/x=t and we have x²+1/x²=t²+2
So 10(t²+2)-63t+52=0
or 10t²-63t+72=0
we have t=(63+33):20= 24/5
and t=(63-33):20=3/2
+ If t=3/2 we have x-1/x=3/2 or 2x²-3x-2=0 and we have x=2, x=-1/2
+ Of t=24/5 we have x-1/x=24/5 or 5x²-24x-5=0 or x=5 and x=-1/5
And the answer: <span>c) (5,2,-1/5,-1/2)</span>
Answer:
1
Step-by-step explanation:
Well you could use the exponential identity that:
To determine: 
Which means that it's equal to: 
and since anything to the power of 0 (except 0) is equal to 1, then the value is 1.
But you can also just see that the numerator and denominator are the same exact value, and since dividing something by it self, results in 1, the answer must be 1, which is kind of a proof as to why h^0 = 1.
Answer:
Step-by-step explanation:
because is not equal
Answer:
Step-by-step explanation:
Amount of water in tank 1 = amount of water in tank 2
30t +25 = -20t + 1000
Add 20t to both sides
30t + 20t + 25 = -20t + 20t + 1000
50t + 25 = 1000
Subtract 25 from both sides
50t + 25 - 25 = 1000 - 25
50t = 975
Divide both sides by 50
t = 975/50 = 39/2

t = 19 minutes 30 seconds
After 19 1/2 minutes both tanks will have 610 liters of water
Answer:
y = 27
Step-by-step explanation:
line segment BA and CD are congruent, turn them into an equation
3y - 59 = y - 5
subtract 1y from both sides, you get 2y - 59 = -5
then, add 59 to both sides and the equation is now 2y = 54
divide each side by 2 and you get the value of y (y = 27)