Answer:
Step-by-step explanation:
The solution of the problem has been solved on paper and attached in the attachment section. Kindly refer to that and feel free to ask any doubt.
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We have that
case 1)
<span>system of equations is
</span><span>y=−12x−1
y=14x−4
using a graph tool
see the attached figure
the solution of the system is the point (0.115,-2.385)
case 2)
</span>system of equations is
<span>blue line passing through coordinates A (0, -4) and B (4, -3)
</span><span>red line passing through coordinates C(0, -1) and D (4, -3)
</span>using a graph tool
see the attached figure
the solution of the system is the point (4,-3)<span>
</span>
case 1)
<span>system of equations is
</span><span>y=−12x−1
y=14x−4
using a graph tool
see the attached figure
the solution of the system is the point (0.115,-2.385)
case 2)
</span>system of equations is
<span>blue line passing through coordinates A (0, -4) and B (4, -3)
</span><span>red line passing through coordinates C(0, -1) and D (4, -3)
</span>using a graph tool
see the attached figure
the solution of the system is the point (4,-3)<span>
</span>
Answer:
y = OR y =
Step-by-step explanation:
Our quadratic equation is: (5y + 6)² = 24.
The first step is to square root both sides:
5y + 6 = ±√24 = ±2√6
Now subtract 6 from both sides:
5y = ±2√6 - 6
Finally divide by 5 from both sides:
y = OR y =
And, those are the solutions to the equation.