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Aneli [31]
3 years ago
10

A hacker is trying to guess someone's password. The hacker knows (somehow) that the password is 13 characters long, and that eac

h character is either a lowercase letter, (a, b, c, etc), an uppercase letter (A, B, C, etc) or a numerical digit (0, 1, 2, 3, 4, 5, 6, 7, 8, or 9). Assume that the hacker makes random guesses.
What is the probability that the hacker guesses the password on his first try? Enter your answer as a decimal or a fraction, not a percentage.
Mathematics
1 answer:
Serhud [2]3 years ago
8 0
There are 26 lowercase and 26 capital letters as well as 10 numerical digits, which makes for 62 total possible characters per spot. Since each of the 13 spots can be any of these 62 digits, the total number of possibilities will be 62^13. Because the hacker has to guess on the first try, he cannot rule out any possibilities. The probability that he will guess the password on the first try is 1/(62^13).
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Answer:

Step-by-step explanation:

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5 0
3 years ago
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A true/false test has 40 questions. Suppose a passing grade is 30 or more correct answers. Test the claim that a student knows m
Angelina_Jolie [31]

Answer:

z≈3.16

p≈0.001

we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

Step-by-step explanation:

As a result of step 2, we can assume normal distribution for the null hypothesis

<em>step 3:</em>

z statistic is computed as follows:

z=\frac{X-M}{\frac{\sqrt{p*(1-p)} }{\sqrt{N} } } where

  • X is the proportion of correct answers in the test (\frac{30}{40})
  • M is the expected proportion of correct answers according to the null hypothesis (0.5)
  • p is the probability of correct answer (0.5)
  • N is the total number of questions in the test (40)

z=\frac{0.75-0.50}{\frac{\sqrt{0.5*(0.5)} }{\sqrt{40} } } ≈ 3.16

And corresponding p value for the z-statistic is p≈0.001.

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7 0
3 years ago
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Answer:

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Step-by-step explanation:

NOTE: This will be solved using simultaneous equations.

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4x + 14 - 2x = 18

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x = 2

5. Now substitute x value into equation (2)

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y = 5

∴ cows (x) = 2

chickens (y) = 5

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