From the graph, when x = 1, y = 57,000.
Replace x with 1 in the equations and see if any of the Y 's equal 57,000 :
y = -2610.82(1) + 47860.82 = 45,250
y = 219(1)^2 - 6,506.78(1) + 59,385 = 219 - 6506.78 + 59385 = 53,097.22
y = 54041.5(0.9)^1 = 48,637.35
y = 10,504.6 (1.1)^1 = 11,555.06
The second equation is the closest. so try another x value to see if it is close to the Y value:
Let's try x = 14:
y = 219(14)^2 - 6506.78(14) + 59,385 = 42924 - 91094.92 + 59385 = 11,214.08
This is close to Y = 12,00 shown on the graph
SO the closest equitation is y = 219x^2 - 6506.78x + 59385
You can use the distance formula: d = sqrt((second x value - first x value)^2 + (second y value - first y value)^2):
answer : d = sqrt((3+2)^2+(6+6)^2) = 11.95826074 units
Answer:
Step-by-step explanation:
Answer:
280000lb
Step-by-step explanation:
In this question, we shall be calculating the amount of carbon iv oxide prevented from entering the atmosphere.
Generally we know that 1kwh produces 1.37 lbs of Carbon iv oxide in the atmosphere
Now, using a 100 watt light bulb daily for 8 hours, for a year, the amount of Carbon iv oxide produced will be;
100 * 1.37 * 8 * 365 = 40040 lb
Using a 30 watt CFL for 8hrs/ day for a year, we have;
30 * 1.37 * 8 * 365 = 120012 lb
Now calculating the amount of CO2 prevented, we have 40040 - 120012 = 280028 lb = 280000 after rounding up
The data set has no association.
