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Nadusha1986 [10]
3 years ago
6

How can we solve the equation 6a = 18?

Mathematics
2 answers:
Ainat [17]3 years ago
4 0

Answer:

D) Divide both sides of the equation by 6

Step-by-step explanation:

6a = 18

a = 3

DIA [1.3K]3 years ago
3 0

divide both sides by 6....

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Please help!! In radians, what is the period of the function y = .5cos5x
Levart [38]

Answer:

(2pi)/5

Step-by-step explanation:

The cosine function cos(x) has a period of 2*pi.

If we change the argument of the cosine, the new argument will have a period of 2*pi. If the new argument is 5x, we have that the period will be:

5x = 2*pi

x = 2*pi/5

The period of this function will be (2pi)/5, because for every (2pi)/5 change in the value of x, the function will have the same value. The value of 5 multiplying the cosine does not interfere in the period.

5 0
3 years ago
Evaluate the integral. W (x2 y2) dx dy dz; W is the pyramid with top vertex at (0, 0, 1) and base vertices at (0, 0, 0), (1, 0,
In-s [12.5K]

Answer:

\mathbf{\iiint_W (x^2+y^2) \ dx \ dy \ dz = \dfrac{2}{15}}

Step-by-step explanation:

Given that:

\iiint_W (x^2+y^2) \ dx \ dy \ dz

where;

the top vertex = (0,0,1) and the  base vertices at (0, 0, 0), (1, 0, 0), (0, 1, 0), and (1, 1, 0)

As such , the region of the bounds of the pyramid is: (0 ≤ x ≤ 1-z, 0 ≤ y ≤ 1-z, 0 ≤ z ≤ 1)

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \int ^{1-z}_0 \int ^{1-z}_0 (x^2+y^2) \ dx \ dy \  dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \int ^{1-z}_0 ( \dfrac{(1-z)^3}{3}+ (1-z)y^2) dy \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0  \ dz \  ( \dfrac{(1-z)^3}{3} \ y + \dfrac {(1-z)y^3)}{3}] ^{1-x}_{0}

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0  \ dz \  ( \dfrac{(1-z)^4}{3}+ \dfrac{(1-z)^4}{3}) \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz =\dfrac{2}{3} \int^1_0 (1-z)^4 \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz =- \dfrac{2}{15}(1-z)^5|^1_0

\mathbf{\iiint_W (x^2+y^2) \ dx \ dy \ dz = \dfrac{2}{15}}

7 0
3 years ago
30 is what percent of 200?​
madam [21]

Answer:

15 percent

Step-by-step explanation:

  • 30/200=15/100
  • 15/100=0.15
  • 0.15=15 percent
5 0
3 years ago
PLEASE HELPP Write the equation of the line fully simplified slope-intercept form.
Mkey [24]
The answer will be: Y = -2/5x - 4

Slope intercept form: y= Mx+b

You find the slope (M) using: rise/run formula
You find (b) by looking at the y-intercept
4 0
3 years ago
What is the circumference and area of the circle
djverab [1.8K]

Answer:

the circumference is: 10.048 ft

the area is: 8.0384 ft

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3 years ago
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