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erastovalidia [21]
2 years ago
14

Ms. Carey is planning to host a neighborhood picnic. To make sure she had enough ingredients, she was making a table of possible

combinations of dried fruit to peanuts for her terrific trail mix. The table shows the original recipe’s ratio of dried fruit to peanuts. What numbers are missing in the table?
Question 5 options:

5 and 48


21 and 35


6 and 10


21 and 62

Mathematics
1 answer:
lukranit [14]2 years ago
6 0

Answer:

5 and 48

Step-by-step explanation:

27:45

Simplify the ratio

3:5

The first one must be 5, and option 1 (5 and 48) is the only one with 5.

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73590 rounded to the nearest thousand
11Alexandr11 [23.1K]
Okay, so here is a small lesson on rounding. When you round you MUST know the place value of each number. Ones, tens, hundreds, thousands, millions.
So, when we look at this number what do we have in the ones place --there is a 0 -- in the tens place we have a 9 and in the the thousands place we have 5. to round this number look at the tens place. if the number is greater than 5 you round 73590 to 73600, if it is 4 and lower it stays the same and the numbers behind change to zero--> like so 73500. But for this problem it would round up to 73600.
5 0
3 years ago
Edgar collects sports T-shirt.He has 16 socoT-shirts and 24 rugby T- shirts. He has 12 hats. Haw many T -shirt does Edgar have i
Marianna [84]
Edgar has 40 shirts. The equation you could write is 24+16=40.  Hope this helps!!
7 0
3 years ago
A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic
goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em>_{i}, of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}

The law of total probability states that, if events <em>E</em>₁, <em>E</em>₂, <em>E</em>₃... are parts of a sample space then for any event <em>A</em>,

P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85

Using the above the probabilities compute the remaining values as follows:

P(X^{c})=1-P(X)=1-0.04=0.96

P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10

P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})

          =(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}

             =\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}

             =0.20

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0
3 years ago
MATH HELP...PLz
PilotLPTM [1.2K]

a. 14, 18, 22, 26.... It is +4

b. 2,430, 7,290, 21,870..... It is x3

c. So it is going -2, -4, -6, -8 so the next one would be -10 which is -13 then -12 which is -25 and so on.

Hope this helps!


8 0
3 years ago
I don’t get the second question.
tatyana61 [14]

it should be 3+(-7)  because look at the number closest to the number line, which is positive 3 then the number next to it is negative 7 because it is heading downward towards the opposing side.  

8 0
3 years ago
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