Quired to the weight
1 answer:
Answer:
The mechanical advantage is 0.25
This mechanical advantage shows that the force at which the deodorant sprays is the quarter of the applied effort, and hence the efficiency of your finger as a machine is 25%.
Explanation:
Given;
output force, F₂ = 15 N
input force, F₁ = 60 N
Mechanical advantage also known as force ratio is defined as the ratio of the output force (load) to the ratio of input force (effort).
This shows that the force at which the deodorant sprays is the quarter of the applied effort, and hence the efficiency of your finger as a machine is 25%.
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Answer:
See explaination code
Explanation:
#include<iostream>
#include<math.h>
using namespace std;
typedef union {
float number;
struct
{
// Order is important.
// Here the members of the union data structure
// use the same memory (32 bits).
// The ordering is taken
// from the LSB to the MSB.
unsigned int mantissa : 23;
unsigned int exponent : 8;
unsigned int sign : 1;
} Raw;
} MyFloat;
void printBinary(int n, int i)
{
// Prints the binary representation
// of a number n up to i-bits.
int k;
for (k = i - 1; k >= 0; k--) {
if ((n >> k) & 1)
cout << "1";
else
cout << "0";
}
}
void decToHex(int n){
// char array to store hexadecimal number
char hexaDeciNum[100];
// counter for hexadecimal number array
int i = 0;
while(n!=0)
{
// temporary variable to store remainder
int temp = 0;
// storing remainder in temp variable.
temp = n % 16;
// check if temp < 10
if(temp < 10)
{
hexaDeciNum[i] = temp + 48;
i++;
}
else
{
hexaDeciNum[i] = temp + 55;
i++;
}
n = n/16;
}
// printing hexadecimal number array in reverse order
for(int j=i-1; j>=0; j--)
cout << hexaDeciNum[j];
}
void floatBinary(float f){
long double binaryTotal, binaryFrac = 0.0, frac, fracFractor = 0.1;
long int integer, binaryInt = 0;
long int p = 0, rem, temp;
//separate the integer part from the input floating number
integer = (int)f;
//separate the fractional part from the input floating number
frac = f - integer;
//loop to convert integer part to binary
while (integer != 0) {
rem = integer % 2;
binaryInt = binaryInt + rem *pow(10, p);
integer = integer / 2;
p++;
}
//loop to convert fractional part to binary
while (frac != 0) {
frac = frac * 2;
temp = frac;
binaryFrac = binaryFrac + fracFractor * temp;
if (temp == 1)
frac = frac - temp;
fracFractor = fracFractor / 10;
}
cout << binaryInt + binaryFrac;
}
int findDecimal(float number){
int nfloor = number;
float nfloat = number - nfloor;
int nfloatfloor;
do {
nfloat *= 10;
nfloatfloor = nfloat;
} while (nfloat > nfloatfloor);
return nfloatfloor;
}
void first(float number){
if(number < 0)
cout << "SIGN BIT IS (1) SINCE NUMBER IS NEGATIVE" << endl;
else
cout << "SIGN BIT IS (0) SINCE NUMBER IS POSITIVE" << endl;
}
void second(float number){
cout << "INTEGER PART IN BASE-10:" << int(number) << " AND IN BINARY:";
printBinary(int(number),16);
cout << endl;
}
void third(float number){
cout << "DECIMAL PART IN BASE-10:" << findDecimal(number) << " AND IN BINARY:";
printBinary(findDecimal(number),16);
cout << endl;
}
void fourth(float number){
cout << "ENTERED NUMBER IN BASE-10:" << number << " AND IN BINARY:";
floatBinary(number);
cout << endl;
}
void fifth(MyFloat myfloat){
cout << "MANTISA IN BINARY:";
printBinary(myfloat.Raw.mantissa,32);
}
void sixth(MyFloat myfloat){
cout << "EXPONENT IN BASE-10:" << myfloat.Raw.exponent << " AND IN BINARY:";
printBinary(myfloat.Raw.exponent,8);
cout << endl;
}
void seventh(MyFloat myfloat){
cout << myfloat.Raw.sign << " | ";
printBinary(myfloat.Raw.exponent,8);
cout << " | ";
printBinary(myfloat.Raw.mantissa,32);
cout << endl;
}
void eigth(MyFloat myfloat){
cout << myfloat.Raw.sign << " | ";
decToHex(myfloat.Raw.exponent);
cout << " | ";
decToHex(myfloat.Raw.mantissa);
cout << endl;
}
int main(){
float number;
cout << "PLEASE ENTER A NUMBER TO DISPLAY THE IEEE 754 FLOATING POINT OPTIONS" << endl;
cin >> number;
MyFloat myfloat;
myfloat.number = number;
cout << "PLEASE CHOOSE ONE OF THE FOLLOWING OPERATIONS" << endl;
cout << " 1. DISPLAY THE SIGN BIT VALUE" << endl;
cout << " 2. DISPLAY THE INTEER PART IN BOTH BASE-10 AND CINARY FORMATS" << endl;
cout << " 3. DISPLAY THE DECIMAL PART IN BOTH BASE-10 AND BINARY FORMATS" << endl;
cout << " 4. DISPLAY THE NUMBER ENTERED IN BOTH BASE-10 AND BINARY FORMATS" << endl;
cout << " 5. DISPLAY THE MANTISA IN BINARY FORMATS" << endl;
cout << " 6. DISPLAY THE EXPONENT IN BORH BASEE-10 AND BINARY FORMATS" << endl;
cout << " 7. DISPLAY THE IEEE 754 SINGLE PRECISION BINARY LAYOUT" << endl;
cout << " 8. DISPLAY THE IEEE 754 SINGLE PRECISION BINARY LAYOUT" << endl;
int choice;
cin >> choice;
switch(choice){
case 1:first(number);
break;
case 2:second(number);
break;
case 3:third(number);
break;
case 4:fourth(number);
break;
case 5:fifth(myfloat);
break;
case 6:sixth(myfloat);
break;
case 7:seventh(myfloat);
break;
case 8:eigth(myfloat);
break;
default:cout << "ENTER VALID CHOICE" << endl;
}
}
Refer to attachment please for onscreen look.
