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Brums [2.3K]
3 years ago
11

If the power of an engine is known and the amount of time that the engine exerts this power is known, what can be calculated?

Physics
1 answer:
Maru [420]3 years ago
4 0
The work done by the engine in a given time.  
Power is the time rate of change of energy, (which is another name for work, both measured in Joules)
So power = energy/time, with units of Joules/second.
Since you know energy per time, if you know the amount of time you can multiply power by time to get energy (work).
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Hermal energy is a form of... A. Potential energy. B. Kinetic energy. C. Chemical energy.
aev [14]

Thermal energy also known as 'heat energy' is a form of kinetic energy.

6 0
3 years ago
Explain the necessity of smoothing the output voltage before applying it to a transistor
ra1l [238]

In simple words, smoothing can be defined as the circuit which is done to eliminate the ripple from the yield of a direct current power supply.

<u>Explanation:</u>

<u>Necessity of smoothing:</u>

  • Smoothing can be also applied in the form of a capacitor that acts to decrease or level out variations in a signal. And these capacitors are mostly used after power supply in voltage.
  • The yield DC voltage of a half-wave rectifier provided in the figure of a sinusoidal wave.
  • In a method to provide a constant DC voltage from a corrected AC source, a filter or smoothing circuit is required.

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6 0
3 years ago
A stun gun or TASER is designed to put out a few seconds worth of electric pulses that impress a
iren [92.7K]

Answer:

Resistance = 400000 Ohms

Explanation:

Given the following data;

Voltage = 1200 V

Current = 3 mA = 3/1000 = 0.003 A

To find the resistance;

Voltage = current * resistance

Resistance = 1200/0.003

Resistance = 400000 Ohms

5 0
3 years ago
Each of the gears a and b has a mass of 675 g and has a radius of gyration of 40 mm, while gear c has a mass of 3. 6 kg and a ra
navik [9.2K]

9.87 seconds

The time required for this system to come to rest is equal to 9.87 seconds.

We have the following data:

Mass of gear A = 675 g to kg = 0.675 kg.

Radius of gear A = 40 mm to m = 0.04 m.

Mass of gear C = 3.6 kg.

Radius of gear C = 100 mm to m = 0.1 m.

How can I calculate the time needed?

We would need to figure out the moment of inertia for gears A and C in order to compute the time needed for this system to come to rest.

Mathematically, the following formula can be used to determine the moment of inertia for a gear:

I = mr²

Where:

m is the mass.

r is the radius.

We have, For gear A:

I = mr²

I = 0.675 × 0.04²

I = 0.675 × 0.0016

I = 1.08 × 10⁻³ kg·m².

We have, For gear C:

I = mr²

I = 3.6 × 0.1²

I = 3.6 × 0.01

I = 0.036 kg·m².

The initial angular velocity of gear C would therefore be converted as follows from rotations per minute (rpm) to radians per second (rad/s):

ωc₁ = 2000 × 2π/60

ωc₁ = 4000π/60

ωc₁ = 209.44 rad/s.

Also, the initial angular velocity of gears A and B is given by:

ωA₁ = ωB₁ = rc/rA × (ωc₁)

ωA₁ = ωB₁ = 0.15/0.06 × (209.44)

ωA₁ = ωB₁ = 2.5 × (209.44)

ωA₁ = ωB₁ = 523.60 rad/s.

Taking the moment about A, we have:

I_A·ωA₁ + rA∫F_{AC}dt - M(f)_A·t = 0

On Substituting the given parameters into the formula, we have;

(1.08 × 10⁻³)·(523.60) + 0.06∫F_{AC}dt - 0.15t = 0

0.15t - 0.06∫F_{AC}dt = 0.56549   ----->equation 1.

Similarly, the moment about B is given by:

0.15t - 0.06∫F_{BC}dt = 0.56549    ------>equation 2.

Note: Let x = ∫F_{BC}dt + ∫F_{AC}dt

Adding eqn. 1 & eqn. 2, we have:

0.3t - 0.06x = (0.56549) × 2

0.3t - 0.06x = 1.13098  ------>equation 3.

Taking the moment about A, we have:

Ic·ωc₁ - rC∫F_{AC}dt - rC∫F_{BC}dt - Mc(f)_A·t = 0

0.036(209.44) - 0.3t - 0.15(∫F_{BC}dt + ∫F_{AC}dt) = 0

0.3t + 0.15x = 7.5398    ------->equation 4.

Solving eqn. 3 and eqn. 4 simultaneously, we have:

x = 30.5 Ns.

Time, t = 9.87 seconds.

To learn more about moment of inertia visit:

brainly.com/question/15246709

#SPJ4

6 0
2 years ago
7. If 8 million kg of water flows over Niagara Falls each second, calculate the power available at the bottom of the falls.
Alexxx [7]

Answer:

The power will be "3.92×10⁹ Watts". A further explanation is given below.

Explanation:

The given values as per the question,

Rate,

= 8 million kg

Distance,

= 50 m

Gravity,

= 9.8 m/s²

As we know,

The power will be:

⇒ Power = Rate\times Distance\times  Gravity

On putting the values, we get

⇒             =  8\times 10^6\times 50\times 9.8

⇒             =3.92\times 10^9 \  Watts

7 0
3 years ago
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