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Mashutka [201]
3 years ago
13

A 1242 kg car is moving at 22.5 m/s when it skids to a stop. The car's brakes, which caused the stop, applied a force of -7210 N

in order to slow down the car. What was the acceleration of the car during it's slowing down to rest?
Physics
1 answer:
Debora [2.8K]3 years ago
8 0

The work needed to stop the car is

<em>W</em> = ∆<em>K</em> = 0 - 1/2 (1242 kg) (22.5 m/s)² ≈ -314 kJ

A stopping force that does this amount of work, pointing in the opposite direction with magnitude 7210 N, would be exerted over a distance <em>x</em> such that

<em>W</em> = (-7210 N) <em>x</em>   ==>   <em>x</em> ≈ 43.6 m

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ikadub [295]

Answer:

1,700feet

Explanation:

If an object in free fall travels a distance s that is directly proportional to the square of the time t, this can be represented mathematically as;

S = kt²where;

k is the proportionality constant

K = s/t²

s1/t1²= s2/t2²= Sn/tn²= k for values of the distance and time. Using the formula

s1/t1² = s2/t2² where;

s1 is the falling distance in time t1 s2 is the falling distance in time t2

Given s1 = 1088feet, t1 = 8secs, s2 = ? t2 = 10secs

Substituting this value in the formula to get s2, we have;

1088/8²= s2/10²

64s2= 108800

s2 = 108800/64

s2 = 1,700feet

This means the object will fall a distance of 1,700feet in 10seconds

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GrogVix [38]
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4 0
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Help? Will give thanks if right (thank you)
qwelly [4]

Hello there.

1.986*10^6

10^6=1,000,000

1.986*1,000,000

<u><em>Answer=1,986,000</em></u>

Explanation: First you had to ten to the six power of the ten with six times. It gave us 1000000 should be have six zeros at any time. Then you can multiply by 1.986*1000000=1,986,000 is the right answer. Hope this helps! Thank you for posting your question at here on Brainly. -Charlie

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Stells [14]

Answer:

Δ h = 52.78 m

Explanation:

given,

Atmospheric pressure at the top of building = 97.6 kPa

Atmospheric pressure at the bottom of building = 98.2 kPa

Density of air = 1.16 kg/m³

acceleration due to gravity, g = 9.8 m/s²

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We know,

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(98.2-97.6) x 10³ = 1.16 x 9.8 x Δ h

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Δ h = 52.78 m

Hence, the height of the building is equal to 52.78 m.

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