A 1242 kg car is moving at 22.5 m/s when it skids to a stop. The car's brakes, which caused the stop, applied a force of -7210 N
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The equivalent of the Newton's second law for rotational motions is:
where
is the net torque acting on the object
is its moment of inertia
is the angular acceleration of the object.
Re-arranging the formula, we get
and since we know the net torque acting on the (vase+potter's wheel) system,
, and its angular acceleration, 
, we can calculate the moment of inertia of the system:
where
Re-arranging the formula, we get
and since we know the net torque acting on the (vase+potter's wheel) system,