First, let's convert X into 4
(3*4 - 4)ft, (4*2 - 1)ft, (2*4*2 - 15)ft
Now lets simplify this a little
(12 - 4)ft, (8 - 1)ft, (16 - 15)ft
Awesome now lets finish up
8 x 9 x 1 / 2 = 36
The answer should be 36ft. Unless I did my math wrong.
1/9
because there are 21 chips in the bag 7 of them are yellow so 7/21
but you draw twice so you square it (7/21)^2=1/9
Answer:
C= 37.69ft
A= 113.09ft
Step-by-step explanation:
Circumference=
=37.69
Area=
Area = pi * 6 ^2
Area =113.09
Answer:
5+60=N
Step-by-step explanation:
its the algebraic way bc it says 5 more so you do 5+
Answer:
a. What is the probability that Carl arrives first?
Probability that Carl arrives first is ¹/₃ = 33.33% since their arrival times is uniformly distributed. The same probability applies to Bob and Alice.
b. What is the probability that Carl will have to wait more than 10 minutes for one of the others to show up?
Assuming that Carl arrived on time, 1:10 PM, we must determine the probability that Alice or Bob arrive between 1:20 and 1:30 (half the remaining time)
P = [3 · (¹/₂ - ¹/₃)] · [3 · (¹/₂ - ¹/₃)] = (3 · ¹/₆) · (3 · ¹/₆) = ¹/₂ · ¹/₂ = ¹/₄ = 25% chance that either Alice or Bob arrive more than 10 minutes later
c. What is the probability that Carl will have to wait more than 10 minutes for both of the others to show up?
P = 1 - 25% = 75%
d. What is the probability that the person who arrives second will have to wait more than 5 minutes for the third person to show up?
I divided the 20 minutes by 5 to get ¹/₄:
P (|S - T| ≤ ¹/₄) = {[(x + ¹/₄)²] / 2} + (1 / 2x) + {[(⁵/₄ - x)²] / 2} = 0.09375 + 0.25 + 0.09375 = 0.4375 = 43.75%
