Answer:
The solution of the differential equation is .
Step-by-step explanation:
The first step is to take Laplace transform in both sides of the differential equation. As usual, we denote the Laplace transform of as . Then,
In the last step we use that and .
Notice that our differential equations becomes an algebraic equation for , which is more simple to solve.
In the expression we have obtained, we can write in terms of :
which is equivalent to
.
Now, we make a partial fraction decomposition for the term . Thus,
.
Substituting the above value into the expression for we get
) in both hands of the above expression. Recall that . So,
.
To obtain this we have used the following identities that can be found in any table of Laplace transforms
X<67/5 :) do u need the work or nah
in general, the graph of y = f(x-a) is a shift a units right if a is positive and shift of a units left if a is negative. for example, y = f(x-2) is 2 units right of f(x) and y=f(x+2) is 2 units LEFT.
in general, the graph of y = f(x) + a is a shift a units up if a is postiive and a units down if a is negtaive. For example, y = f(x) + 4 is 4 units up and y=f(x)-4 is a shift of 4 units down.
Note that f(x) = sqrt(x) here, so we have f(x+4) = sqrt(x+4) for 4 units left. Then you do f(x+4) + 6 = sqrt(x+4) + 6 for 6 units up.
Your answer is g(x) = sqrt(x+4) + 6
common difference, d = -3
f1 = -13
An arithmetic sequence f(n) = f1 + d(n - 1)
so f(n) = -13 - 3(n - 1)
f(46) = -13 - 3(46-1) = -13 -3(45) = -13 - 135 = -148
Answer:
f(46) = - 148