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krek1111 [17]
3 years ago
11

Type A Type B Total Batch 1 30 15 45 Batch 2 20 40 60 Batch 3 20 25 45 Total 70 80 150 The table shows the batch number and type

of item for 150 items. If an item from batch 2 is selected at random, what is the probability that the item is type A? 20 40 20 60 20 70 20 150
Mathematics
1 answer:
sleet_krkn [62]3 years ago
5 0

Answer:

20/70 i think ;)

Step-by-step explanation:

becuaswew if u ad the 20, 20 , 30 it equals 70 wich is the denominator

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Answer:

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Step-by-step explanation:

We have to calculate the mean and variance of a sum of random normal variables.

We can apply the rule for mean and variance for sum of independent variables:

X=L+M\\\\E(X)=E(L+M)=E(L)+E(M)\\\\V(X)=V(L+M)=V(L)+V(M)-2CoV(L,M)=V(L)+V(M)

Then, the mean and variance of X is:

E(X)=E(L)+E(M)=15+10=25\\\\\\V(X)=V(L)+V(M)=2^2+2^2=4+4=8\\\\\sigma_x=\sqrt{V(X)}=\sqrt{8}\approx2.83

We can calculate the probability that X is between 22 and 28 as:

z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{22-25}{2.83}=\dfrac{-3}{2.83}=-1.06\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{28-25}{2.83}=\dfrac{3}{2.83}=1.06\\\\\\P(22

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