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2 years ago

Solve the slope for the table.

Mathematics

2 answers:

Liula [17]2 years ago

7 0

The slope is zero I think

Nikitich [7]2 years ago

3 0

Answer:

The slope is 0

Step-by-step explanation:

All y-values are equal to 5 meaning the graph is a straight horizontal line. Slope is the rate at which a graph increases or decreases. Seeing as this graph doesn't do so, the slope is 0.

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Of the following options, what could be a possible first step in solving the equation 8x + 3 = 2x − 15?

miskamm [114]

B.Adding 15 to both sides of the equation.

A. Adding 8x to both sides wouldn't cancel anything out.
B. Adding 15 to both sides will cancel out 15 making it easier to solve for x.
C.Adding 3 to both sides will not cancel anything out.
D. Adding 2x to both sides won't cancel anything out.

4 0

3 years ago

Need help! Does anyone know how to do this type of math? (It's geometry)

mart [117]

Answer:

Step-by-step explanation:

refer the attachment

to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that tangents which meet at the same point are equal that is being said

FA=AI=17
CH=CG=2.5

since $\rm BA=FA+FB$ and it's given that FA and BA are 17 and 29 FB should be

$\rm 29=17+FB$

therefore,

$FB=29-17=\boxed{12}$

once again by two tangent theorem we acquire:

$FB=BH=\boxed{12}$

As BC=BH+CH,BC is

12+2.5
$\boxed{14.5}$

likewise,AD=AI+DI so,

21=17+DI [AD=21(given) and AI=17 (by the theorem)]

thus,

DI=21-17= $\boxed{4}$

By the theorem we obtain:

DI=DG=4

Similarly,DC=DG+CH therefore,

DC=4+2.5= $\boxed{6.5}$

Now finding the Perimeter of ABCD

$P_{\text{ABCD}}=\text{AB+AD+BC+DC}$

substitute what we have and got

$P_{\text{ABCD}}=\text{29+21+14.5+6.5}$

simplify addition:

$P_{\text{ABCD}}=\boxed{71}$

hence,

the Perimeter of ABCD is 71

4 0

2 years ago

A factory received an order for 1,758 laptops. For the first 6 days, it produced 125 laptops per day. If it was asked to finish

BartSMP [9]

Answer:

252 laptops

Step-by-step explanation:

Target number is 1758

Produced in 6 days:

6*125 = 750

Remaining to produce:

1758 - 750= 1008

Days left- 4

Should produce per day:

1008/4 = 252 laptops

8 0

3 years ago

The sum of three consecutive numbers is greater than 40. The inequality that represents this is x + x + 1 + x + 2 > 40. Which

Brut [27]

Answer:

3x ＞ 37

x ＞ 12.333

Thus, 13 and 15 satisfy

Step-by-step explanation:

hope this helps

3 0

3 years ago

Read 2 more answers

Assume that there is a 4% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit

kap26 [50]

Answer:

a) 99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b) 99.999744% probability that during a year, you can avoid catastrophe with at least one working drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

4% rate of disk drive failure in a year.

This means that 96% work correctly, $p = 0.96$

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 2$

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984$

99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b. If copies of all your computer data are stored on four independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 4$