Answer:
The highest floor that the ladder could safely reach is approximately 38.73 feet
Step-by-step explanation:
OSHA requirement for the use of non-self-supporting ladders includes the requirement that the horizontal distance between the point at the top where the ladder is supported and the foot of the ladder should be about a quarter of the ladder's working length
The given length of the longest ladder available at hardware stores, l = 40 feet
Therefore;
The horizontal distance between top support and the foot of the ladder, d = 1/4 × 40 feet = 10 feet
According to Pythagoras theorem, the height, 'h', of the ladder is goven as follows;
l² = d² + h²
∴ h² = l² - d²
Therefore, we have;
h² = 40² - 10² = 1500
h = √1500 = 10·√15
Therefore, the height of the highest floor that can be safely reached with the ladder, h = 10·√15 feet ≈ 38.73 feet.
So,
Each separate term is separated by an addition or subtraction sign.
2x - 9xy + 17y
2x is a term.
-9xy is a term.
17y is a term.
There are three terms. This makes it a trinomial.
5. f(x) = 4 . 7^x
for x = -1
f(-1) = 4 . (7)^-1 = 4/7
for x = 2
f(2) = 4 . (7)^2 = 4 . 49 = 196
17. x^2 - 8x = 9
x^2 -8x + 16 = 9 +16
(x - 4)^2 = 25
(x - 4) = +/-5
x = 5 + 4 = 9 and x = -5 + 4 = -1
18. 3x^2 -5x + 4 = 0
Discriminant √(b^2 - 4ac) = √[(-5)^2 - 4(3)(4)] = √[25 - 48] = √(-23)
Given that √(-23) is an imaginary number, the equation does not have real solutions.
Answer:
3
Step-by-step explanation:
1/5 × 15
= 15/5
= 3 (would love if you could mark me the brainliest :))