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Masteriza [31]
3 years ago
15

What composite number between 50 and 60 both of the factors that form are prime numbers themselves which number is it?

Mathematics
1 answer:
Orlov [11]3 years ago
6 0
51 = 3 * 17, sum of 20, no good. 
<span>52 = 2 * 2 * 13, sum of 17, no good. </span>
<span>54 = 2 * 3 * 3 *3, sum of 11. </span>

<span>The answer is 54. If you need more help, let me know.</span>
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Simplify each expression by distributing and combining like terms <br> 4(x+5)+2
faltersainse [42]

Answer:

4x+22

Step-by-step explanation:

In pic

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3 0
3 years ago
What’s 1+1 x 2x2+6x5 then what is 5x7x6x8
mariarad [96]

Answer:

1+1 x 2x2+6x5 = 35

5*7*6*8 = 1680

Step-by-step explanation:

Order of operation

1+1 x 2x2+6x5 =   1 +  2*2  +  30  = 1 + 4 + 30    do the multiplication first from left to right

then

1 + 4 + 30 = 5 + 30

5+30 = 35     after doing addition

so

1+1 x 2x2+6x5 = 35

5*7*6*8 =  35*48 = 1680

5*7*6*8 = 1680

5 0
3 years ago
Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the pop
Andreyy89

Answer:

The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

Step-by-step explanation:

The complete question is:

The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.

Solution:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical value of <em>z</em> for 90% confidence level is:

<em>z</em> = 1.645

Compute the required sample size as follows:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\cdot\sigma}{MOE}]^{2}\\\\=[\frac{1.645\times 2103}{500}]^{2}\\\\=47.8707620769\\\\\approx 48

Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

3 0
3 years ago
Analyze the number line below and answer the question that follows
Bingel [31]
Where is the number line?
6 0
3 years ago
If VUW is equiangular, find k and t.
Alenkinab [10]

Answer:

C. k=68, t=52

Step-by-step explanation:

Let u, v, y represent the measures of the unmarked angles at the respective vertices. The angles of the equiangular triangle are all 180°/3 = 60°, so we have the relations ...

  • y=v
  • y+v+k = 180
  • v+64+60 = 180
  • u=64
  • u+64+t = 180

From these relations, we know that

... v = 180 -124 = 56 . . . . . 3rd equation above

... 56 +56 +k = 180 . . . . . . 2nd equation above, with y=v=56

... k = 180 -112 = 68 . . . . . above with 112 subtracted

... t = 180 -128 = 52 . . . . . 5th equation above with u=64 and 128 subtracted

8 0
3 years ago
Read 2 more answers
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