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expeople1 [14]
3 years ago
12

If a force of 1.4N is applied to a block with a mass of 7kg, what is the acceleration of the block in meters per second squared?

Chemistry
2 answers:
Troyanec [42]3 years ago
8 0

8,394m2 for 7kg with force 1.4

Anton [14]3 years ago
5 0

Answer:

<h2>0.2 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{1.4}{7} =  \frac{1}{5}   \\

We have the final answer as

<h3>0.2 m/s²</h3>

Hope this helps you

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Answer:

Explanation:

From the information given:

oxidation of oxidized solution takes place at 950° C

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The linear and parabolic coefficient can be computed as:

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Using D_o and E_a values obtained from the graph:

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\dfrac{B}{A} = 1.63 \times 10^8 exp \Big [ \dfrac{-2.05}{8.617 \times 10^{_-5}\times 1173}\Big] \\ \\ = 0.2535 \ \ \mu m/hr

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So, the initial time required to grow oxidation is expressed as:

t_{ox} = \dfrac{x}{B/A}+ \dfrac{x^2}{B} - t_o (initial)

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d_o = \dfrac{-(0.6781) \pm \sqrt{(0.6781)^2-4(1)(-0.245)}}{2(10)}

d_o = \dfrac{-(0.6781) \pm \sqrt{0.45981961+0.98}}{20}

d_o = \dfrac{-(0.6781) \pm \sqrt{1.43981961}}{20}

d_o = \dfrac{-(0.6781) + \sqrt{1.43981961}}{20} \ OR \   \dfrac{-(0.6781) - \sqrt{1.43981961}}{20}

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<u>Answer:</u>

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