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Nadya [2.5K]
3 years ago
6

In the reactions,A products with the concentration [A]0=1.512M,[A]is found to be 1.496at t=30S.With the initial concentration [A

]0=2.584M,[A]is found to be 2.552M at t=1minute.What's the order of
Chemistry
1 answer:
Contact [7]3 years ago
8 0

Answer:

Zero order

Explanation:

Reaction rate for experiment 1 =

1.496 - 1.512 / 30 - 0 = - 5.3 * 10^-4 Ms-1

Reaction rate for experiment 2

2.552 - 2.584/60 - 0 =  - 5.3 * 10^-4 Ms-1

So,

Since the rate of reaction does not change with change in concentration of reactants (identified by the fact that the rates of reaction 1 and reaction 2 are the same), the reaction is zero order.

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Answer:

0.147 mol

Explanation:

Step 1: Calculate the volumetric concentration (Cv)

We will use the following expression.

Cv = Cg × ρ

Cv = 98.0 g%g × 1.84 g/mL = 180 g%mL

Step 2: Calculate the molarity of sulfuric acid

We will use the following expression.

M = mass solute / molar mass solute × liters of solution

M = 180 g / 98.08 g/mol × 0.100 L = 18.4 M

Step 3: Calculate the moles of solute in 8.00 mL of solution

8.00 × 10⁻³ L × 18.4 mol/L = 0.147 mol

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Answer:

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Explanation:

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The new species are created in nature by four mechanisms such as geographic isolation (allopatric speciation), reproductive isolation (sympatric speciation), mating behaviour (parapatric speciation).

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