Answer:
0.83 mL
Explanation:
Given data
- Initial concentration (C₁): 12 M
- Final concentration (C₂): 1.0 M
- Final volume (V₂): 10.0 mL
We can calculate the initial volume of HCl using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂ / C₁
V₁ = 1.0 M × 10.0 mL / 12 M
V₁ = 0.83 mL
The required volume of the initial solution is 0.83 mL.
If the half life is 5 days, you would have to divide 222 by 2 3 times.
so 222/2 =111g
111/2 = 55.5g
55.5/2 = 27.75g
after four half life the mass would be
27.75/2
13.875g
the percent would be
13.875/222
= 6.25%
Answer:
Using general gas laws
P1V1/T1 = P2V2/T2
Where P1=380torr = 380mmHg
Vi = 750ml = 0.75dm3
T1= 8c = 281k
P2=0.2torr= 0.2mmHg
T2= 75c = 348k
V2=?
(380*0.75)/281 = (0.2*V2)/348
V2= 1764.77
Explanation:
