Answer: 0.4375 mols of solute
Explanation:
The problem is asking for the amount of solute. We are given the value of molarity. The molarity is 0.25M. We know that molarity is . Since we are given the liters of solution is 1.75, we can use those values to solve for mols of solute.
[multiply both sides by 1.75 L]
There are 0.4375 mols of solute.
Answer:
1.18 × 10⁷ c
Iron is the anode and zinc is the cathode.
Explanation:
Let's consider the reduction of Zn²⁺.
Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)
<em>How many coulombs of charge are needed to produce 61.2 mol of solid zinc?</em>
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We can establish the following relations:
Then, for 61.2 mol of Zn:
<em>Identify the anode and cathode when plating an iron nail with zinc.</em>
The anode is where the oxidation takes place and the cathode is where the reduction takes place.
Anode (oxidation): Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻
Cathode (reduction): Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)