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My name is Ann [436]
2 years ago
8

Which of the following is an empirical formula? H6O2 H402 H2O H2O2

Chemistry
2 answers:
Jobisdone [24]2 years ago
6 0

Answer:

hola responderé

Explanation:

el h2o es agua y el agua es mojada gracias por su atención

topjm [15]2 years ago
5 0

{\qquad\qquad\huge\underline{{\sf Answer}}}

<h3>What does an empirical formula mean ? </h3>

- Empirical formula represents a molecule with its elements combined in simplest ratio, it's not necessarily same as the form in which the compound really exists in the nature. Hence we can say that empirical formula shows the simple ratios in which atoms combined to form a molecule.

For example : Hydrogen peroxide

- Hydrogen peroxide exists in nature as \sf H_2O_2, which is its molecular formula.

but it's empirical formula will be H0 [ simplest ratio of 1 : 1 ]

Therefore, the correct choice is :

  • C. \sf H_2O

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Explanation:\

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The energy is stored in the bonds between atoms. The bonds absorb energy as they are put under stress and release the energy as they relax (when the object returns to its original shape).

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RAM

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3 years ago
Question 26 Suppose a flask is filled with of and of . The following reaction becomes possible: The equilibrium constant for thi
Blizzard [7]

Answer:

0.36 M

Explanation:

There is some info missing. I think this is the complete question.

<em>Suppose a 250 mL flask is filled with 0.30 mol of N₂ and 0.70 mol of NO. The following reaction becomes possible: </em>

<em>N₂(g) +O₂(g) ⇄ 2 NO(g) </em>

<em>The equilibrium constant K for this reaction is 7.70 at the temperature of the flask.  Calculate the equilibrium molarity of O₂. Round your answer to two decimal places.</em>

<em />

Initially, there is no O₂, so the reaction can only proceed to the left to attain equilibrium. The initial concentrations of the other substances are:

[N₂] = 0.30 mol / 0.250 L = 1.2 M

[NO] = 0.70 mol / 0.250 L = 2.8 M

We can find the concentrations at equilibrium using an ICE Chart. We recognize 3 stages (Initial, Change, and Equilibrium) and complete each row with the concentration or change in the concentration.

    N₂(g) +O₂(g) ⇄ 2 NO(g)

I    1.2        0              2.8

C  +x         +x            -2x

E  1.2+x      x           2.8 - 2x

The equilibrium constant (K) is:

K=7.70=\frac{[NO]^{2}}{[N_{2}][O_{2}]} =\frac{(2.8-2x)^{2} }{(1.2+x).x}

Solving for x, the positive one is x = 0.3601 M

[O₂] = 0.3601 M ≈ 0.36 M

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